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3 years ago

Question 1 (4 points)

Chemistry

2 answers:

anyanavicka [17]3 years ago

8 0

It’s true I hope this help love u k :)

Ivahew [28]3 years ago

6 0

Answer:

it is true.....................

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Which statement best explains why cells separate and expel waste?

STatiana [176]

Answer:

I would say the 2nd one It helps growth and repair of cells of orgasms
But your school would probably say the 3rd one It helps remove toxins from the body to maintain homeostasis

Explanation:

2. Our cells produce a lot of waste that must be eliminated (excreted) from the body. These residues are called excreta. The residues formed from the chemical reactions that take place inside the cells can be eliminated through:

• of the respiratory system (carbon dioxide)

• skin (sweat)

urinary system (urine)

Our cells expel these substances to maintain the dynamic balance (homeostasis) of our body and promote our well-being.

4 0

3 years ago

The standard free-energy changes for the reactions below are given.Phosphocreatine → creatine + Pi ∆ G'° = –43.0 kJ/molATP → ADP

Anton [14]

Answer:

Gibbs free-energy of the reaction = (–12.5 kJ/mol)

Explanation:

The Gibbs free-energy of a reaction predicts the spontaneity or feasibility of a given chemical reaction.

Given the standard Gibbs free energy changes:

Phosphocreatine → creatine + Pi, ∆G° = –43.0 kJ/mol ...(1)

ATP → ADP + Pi , ∆G° = –30.5 kJ/mol ....(2)

Now to calculate the Gibbs free-energy of the given chemical reaction: Phosphocreatine + ADP → creatine + ATP; the equation (2) is reversed to give:

ADP + Pi → ATP, ∆G° = + 30.5 kJ/mol ...(3)

Now the equation (3) and (1) are added, to give:

Phosphocreatine + ADP + Pi→ creatine + ATP + Pi

⇒ Phosphocreatine + ADP → creatine + ATP

Therefore, to calculate the Gibbs free-energy of the reaction, the standard Gibbs free energy changes of the equations (1) and (3) are added similarly:

Gibbs free-energy of the reaction: ∆G° = (–43.0 kJ/mol) + ( + 30.5 kJ/mol) = (–12.5 kJ/mol)

Therefore, the Gibbs free-energy of the reaction = (–12.5 kJ/mol)

7 0

3 years ago

What is one main role of state governments?

mr Goodwill [35]

C.commanding the army the the navy would be right I think

7 0

2 years ago

Read 2 more answers

Help ASAP wil give brainlist pls

olganol [36]

2A3B ---- 4A2 + B2

It is a balancing equation right?

3 0

3 years ago

For each of the scenarios, identify the order with respect to the reactant, A. A⟶products The half‑life of A increases as the in

nirvana33 [79]

Answer:

Answers are in the explanation.

Explanation:

The half‑life of A increases as the initial concentration of A decreases. order: 2. In the half-life of second-order reactions, the half-life is inversely proportional to initial concentration.
A three‑fold increase in the initial concentration of A leads to a nine‑fold increase in the initial rate. order: 2. The rate law of second-order is: rate = k[A]²
A three‑fold increase in the initial concentration of A leads to a 1.73‑fold increase in the initial rate. order: 1/2. The rate law for this reaction is: rate = k √[A]
The time required for [A] to decrease from [A]₀ to [A]₀/2 is equal to the time required for [A] to decrease from [A]₀/2 to [A]₀/4. order: 1. The concentration-time equation for first-order reaction is: ln[A] = ln[A]₀ - kt. That means the [A] decreasing logarithmically.
The rate of decrease of [A] is a constant. order: 0. The rate law is: rate = k -where k is a constant-

4 0

3 years ago