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Vadim26 [7]
3 years ago
5

Carbon-14 has a radioactive half-life of 5700 years. If an organism has 11.24 g of carbon-14 in its body at the time of its deat

h, how much carbon 14 will remain after 6350 years?
Chemistry
1 answer:
SVETLANKA909090 [29]3 years ago
5 0

Answer:

= 5.193 g

Explanation:

Half life is the time taken by a radioactive element to decay by half its original amount. Therefore, since half life of carbon-14 is 5700 years, then it would take 5700 years for a sample of carbon-14 to decay by half of its original amount.

Using the formula;

New mass = Original mass × (1/2)^n, where n is the number of half lives.

n = Period taken/Half life = 6350 years/5700 years =1.114

Therefore;

New mass = 11.24 × (1/2)^1.114

                 = 5.193 g

Hence, a mass of 5.193 g of Carbon-14 would remain after 6350 years.

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Hydrolamine ,NH2OH , is a reducing agent found in some film developing solutions. How many hydrogen atoms are in 1.80moles of hy
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Answer:

number of hydrogen atom in 1.8 mole of NH2OH = 9.8\times 10^{22}

Explanation:

percentage of hydrogen in NH2OH = mass of hydrogen / mass of whole molecule

                                                             =\frac{3\times 1}{14+3+16}\times 100

                                                             = 9.09 percentage

therefore number of moles in 1.8 moles of hydroxy amine = \frac{9.09}{100}\times 1.8

                                                                = .16 moles of hydrogen

number of hydrogen atom = (number of moles )×(avagadro number)

                                              = 9.8\times 10^{22} atoms of hydrogen

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3 years ago
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2 years ago
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What volume (mL) of concentrated solution of magnesium chloride (9.00 M) must be diluted to 350. mL to make a 2.75 M solution of
zalisa [80]

❤Answer

<u>Volume </u><u>of</u><u> 106.9 mL from the concentrated solution should be taken and diluted to 350 </u><u>mL.</u>

⠀

⠀

<u>Main I'd On Indian Brainly Is - HeartCrush</u>

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<u>We can use the </u><u>formula.</u><u> </u>

c1v1 =c2v2

<u>Where c1 is the concentration and v1 is volume of the concentrated </u><u>solution.</u><u> </u>

c2 is the concentration

and v2 is the volume of the diluted solution to be prepared

9.00 M x V1 = 2.75 M x 350 mL

V1 = 106.9 mL

<u>Volume of 106.9 mL from the concentrated solution should be taken and diluted to 350 </u><u>mL</u><u>.</u>

3 0
2 years ago
What is the chemical formula of calcium chloride?
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➷ It would be CaCl2

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7 0
3 years ago
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A brick has a mass of and the Earth has a mass of . Use this information to answer the questions below. Be sure your answers hav
weeeeeb [17]

The given question is incomplete. The complete question is:

A brick has a mass of 4.0 kg and the earth has a mass of 6.0\times 10^{27}g Use this information to answer the questions below. Be sure your answers have the correct number of significant digits. What is the mass of 1 mole of bricks? Round your answer to 2 significant digits. How many moles of bricks have a mass equal to the mass of the Earth? Round your answer to 2 significant digits.

Answer: The mass of 1 mole of bricks is 2.4\times 10^{27}g

2.5 moles of bricks have a mass equal to the mass of the Earth

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

Mass of 1 brick = 4.0 kg = 4000 g     (1kg=1000g)

Thus mass of 1 mole of brick or 6.023\times 10^{23} bricks will be = \frac{4000g}{1}\times 6.023\times 10^{23}=2.4\times 10^{27}g

The mass of 1 mole of bricks is 2.4\times 10^{27}g

Now 2.4\times 10^{27}g will correspond to = 1 mole of bricks

6.0\times 10^{27}g will correspond to =\frac{1}{2.4\times 10^{27}}\times 6.0\times 10^{27}=2.5moles

2.5 moles of bricks have a mass equal to the mass of the Earth

5 0
2 years ago
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