The E(incident) for the first polarizer is E(incident)=-76.1930384332
The E(incident) for the second polarizer is E(incident)=12.340115991
<u>Explanation:</u>
<u>Solving the problem:</u>
<u>Given</u>
Transmitted data = 80 mW
First polarizer= 30 degree
Second polarizer= 60 degree
We have the formula,
E (transmitted) = E (incident)cos()
<u>1. Through the first polarizer</u>
E (transmitted) = E (incident)cos()
80=E(incident) cos(60 degree) (according to law subtract the given degree with 90 degree).
Then,
E(incident)=E(transmitted) cos()
E(incident) =80×cos 60 degree
E(incident)=-76.1930384332
The E(incident) for the first polarizer is E(incident)=-76.1930384332
<u>2. Through the first polarizer</u>
We have the formula,
E (transmitted) = E (incident)cos()
80=E(incident) cos(30 degree) (according to law subtract the given degree with 90 degree).
Then,
E(incident)=E(transmitted) cos()
E(incident) =80×cos 30 degree
E(incident) =12.340115991
The E(incident) for the second polarizer is E(incident)=12.340115991
<u></u>
