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Delvig [45]
3 years ago
10

Resistance in wires causes which of the following to occur?

Physics
2 answers:
Novay_Z [31]3 years ago
4 0

Answer: C. causes thermal energy

Explanation: Resistance in wires basically creates obstruction in the path of the current flow.

This obstruction results in a collision for the charge carrying electrons. This collision thus converts the kinetic energy of the electrons into thermal energy in the form of heat.

Resistance reduces the amount of current flowing through a conductor and hence less current means less power resulting in loss of brightness.

Natasha_Volkova [10]3 years ago
3 0

Resistance in wires causes thermal energy. The correct answer between all the choices given is the third choice or letter C. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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An object, with a final position of x = 100.1 meters, initially started at x = -12.13 meters. What was its displacement? (Unit =
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112.23 m

Explanation:

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a skier is gliding along 3.0 m/s on horizontal, frictionless snow. he suddenly starts down a 10 degrees incline. his speed at th
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... find length
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only force act on skier is mg vertically. spilt vector we get force along the incline = mgsin(10) and f= ma so
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Air enters a turbine operating at steady state with a pressure of 75 Ibf/in.^2, a temperature of 800º R and velocity of 400 ft/s
Arturiano [62]

Answer:

(a) W/m = 49.334 Btu/lb

(b) \frac{E_{d} }{m} = 22.12 Btu/lb

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For the given problem, it can be assumed that the system is operating at steady state and the effects of potential energy can be neglected.

(a) Using the thermodynamic table for air.

At the temperature (T_{1})of 800 ºR and pressure (P_{1}) of 75 Ibf/in.^2, we can deduce that:

Specific enthalpy (h_{1}) = 191.81 BTu/lb

Specific entropy (s_{1}) = 0.6956 Btu/(lb.ºR)

At the temperature (T_{2})of 600 ºR and pressure (P_{2}) of 15 Ibf/in.^2, we can deduce that:

Specific enthalpy (h_{2}) = 143.47 BTu/lb

Specific entropy (s_{2}) = 0.6261 Btu/(lb.ºR)

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\frac{W}{m} = -2 + (191.81 - 143.47) + \frac{400^{2} - 100^{2}}{2}*[tex]\frac{1}{2*32.2*778}[/tex] = -2 + 48.34 + 29.938 = 49.334 Btu/lb

(b) To calculate the exergy destruction, we will use the equation for exergy rate:

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