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ioda
3 years ago
9

(03.02 MC) Two students made the following statements to describe atmospheric conditions at a location. Student A: This area has

been covered with snow for the past thousand years. Student B: The city experiences dry winters. Which of these is true about the two statements? They both described climate. They both described weather. Student A described climate and Student B described weather. Student A described weather and Student B described climate.
Physics
1 answer:
olganol [36]3 years ago
3 0

Answer:

it is d

Explanation:

cause i am smort

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During a free fall Swati was accelerating at -9.8m/s2. After 120 seconds how far did she travel? Use the formula =1/2 * t2 to so
Ulleksa [173]

8/9 score.....................

3 0
2 years ago
Read 2 more answers
Click to review the online content. Then answer the question(s) below, using complete sentences. Scroll down to view additional
Nostrana [21]

Answer:

The general shape of a frequency distribution. For many data sets, statisticians use this information to determine whether there is a “normal” distribution of values. In normal distributions, the mean, median, and mode are the same. Whether the distribution is symmetrical or skewed in a certain direction. If the data is skewed to the right, this shows the mean will be greater than the median. Similarly, if the data is skewed left, the mean will be less than the median. The symmetry, or asymmetry, of the chart can help statisticians calculate probability. The modality of the data set. This means how many peaks exist in the data. For normal distributions, there will be one peak, or mode, in the data set.

Explanation:

i just got it right on edgenuity :)

6 0
3 years ago
A grandfather clock has a pendulum that consists of a thin brass disk of radius r = 13.62 cm and mass 1.199 kg that is attached
Feliz [49]

Answer:

Explanation:

Expression for time period of a pendulum is as follows

T = 2\pi\sqrt{\frac{l}{g} }

l is length of pendulum from centre of bob and g is acceleration due to gravity

Given

Time period T = 1.583

g = 9.846

Substituting the values

1.583 = 2\pi\sqrt{\frac{l}{9.846} }

l = \frac{(1.583)^2\times9.846}{4\times(\frac{22}{7})^2 }

l = .6244 m

= 62.44 cm

Length of rod  = length of pendulum - radius of bob

= 62.44 - 13.62

= 48.82 cm

= .488 m

8 0
2 years ago
Suppose you exert a 400-N force on a wall but the wall does not move. The work you are doing on the wall is : unknown, because t
Ilya [14]

Answer:

W = 0 :The work done on the wall is zero,because the wall is not moving

Explanation:

Work theory

Work is the product of a force applied to a body and the displacement of the body in the direction of this force.

W= F*d Formula (1)

W: Work (Joules) (J)

F: force applied (N)

d=displacement of the body (m)

The work is positive (W+) if the force goes in the same direction of movement.

The work is negative (W-)if the force goes in the opposite direction to the movement

Data

F= 400-N

d= 0

Problem development

We apply formula (1) to calculate the work done on the wall:

W= 400*0

W=0

6 0
3 years ago
B) If the actual counterweight fitted to this boom was
Lostsunrise [7]

Answer:

50 N

4.2 N

Explanation:

i) The force needed to balance the boom is 2400 N.  If the weight of the counterbalance is 2350 N, then the downward force the park attendant must apply is 50 N.

ii) When the boom is resting on the end support, the normal force is:

∑τ = Iα

-W (0.50) + F (3.0) − N (6.0) = 0

-0.50 W + 3.0 F = 6.0 N

N = (-0.50 W + 3.0 F) / 6.0

N = (-0.50 × 2350 + 3.0 × 400) / 6.0

N ≈ 4.2

6 0
2 years ago
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