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3 years ago

13

A boulder on top of a cliff has a potential energy of 12400J. How high above is the boulder?

1 answer:

Bezzdna [24]3 years ago

6 0

Do you also know what the mass of the boulder is?

You might be interested in

State Archimedes' principle

OlgaM077 [116]

Explanation:

Archimedes' principle states that the upward buoyant force which is exerted on body when immersed whether fully submerged or partially in the fluid is equal to weight of fluid which body displaces and this force acts in upward direction at center of mass of displaced fluid.

Thus,

<u>Weight of the displaced fluid = Weight of the object - Weight of object in fluid.</u>

6 0

3 years ago

the earth has a radius of 6.38×10^16 meter and turns around once on its axis in 24 hour.what is the radial acceleration of perso

Scrat [10]

337493603.8m/s²

Explanation:

Radius of the earth = 6.38 x 10¹⁶m

time = 24hr (86400s)

Unknown:

Centripetal acceleration = ?

Solution:

The centripetal acceleration is directed inward to keep the body from falling off the surface of the earth.

centripetal acceleration = $\frac{v^{2} }{r}$

where v is the velocity and r is the radius

also;

v = wr

where w is the angular velocity

substituting in the equation for centripetal acceleration gives;

a = w²r

also w = $\frac{2 x pi}{T}$

therefore;

a = $\frac{4 \pi ^{2} r }{T^{2} }$

a = $\frac{ 4 x 3.142^{2} x 6.38 x 10^{16} }{86400^{2} }$

a = 337493603.8m/s²

learn more:

Acceleration brainly.com/question/3820012

#learnwithBrainly

5 0

4 years ago

4. Ano ang matinding suliranin ang kakaharapin kapag patuloy ang pagkasira ng

jasenka [17]

Answer:

I think its D

Explanation:

Kasi Pinoy ako

5 0

3 years ago

Read 2 more answers

When a light wave enters into a medium of different optical density,

olga nikolaevna [1]

I think it should be option (b)

6 0

3 years ago

A Neglecting air resistance, a ball projected straight upward so it remains in the air for 10 seconds needs an initial speed of

ololo11 [35]

Answer:

The initial velocity is 50 m/s.

(C) is correct option.

Explanation:

Given that,

Time = 10 sec

For first half,

We need to calculate the height

Using equation of motion

$v^2=u^2+2gh$

$h =\dfrac{v^2}{2g}$ ....(I)

For second half,

We need to calculate the time

Using equation of motion

$h =ut+\dfrac{1}{2}gt_{2}^2$

$h=0+\dfrac{1}{2}gt_{2}^2$

$t_{2}=\sqrt{\dfrac{2h}{g}}$

Put the value of h from equation (I)

$t_{2}=\sqrt{\dfrac{2\times v^2}{g^2}}$

$t_{2}=\dfrac{v}{g}$

According to question,

$t_{1}+t_{2}=10$

$t_{1}=t_{2}$

Put the value of t₁ and t₂

$\dfrac{v}{g}+\dfrac{v}{g}=10$

$\dfrac{2v}{g}=10$

$v=\dfrac{10\times g}{2}$

Here, g = 10

The initial velocity is

$v=\dfrac{10\times10}{2}$

$v=50\ m/s$

Hence, The initial velocity is 50 m/s.

3 0

3 years ago