4 years ago

A boulder on top of a cliff has a potential energy of 12400J. How high above is the boulder?

Physics

1 answer:

Bezzdna [24]4 years ago

6 0

Do you also know what the mass of the boulder is?

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Oo hi granger ru online here i have a doubt in physics .

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Answer:

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3 years ago

Olivia bought new gym shoes to play volleyball because she kept slipping when she ran in her old shoes .how will the new soles h

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By the grip on the bottom

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4 years ago

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Give reasons.<br>A stone thrown upward returns back to the earth surface.

Wittaler [7]

Answer:

Gravity

Explanation:

Due to earths gravity, anything that goes into the air returns back to the surface unless it is given the ability to fly.

Hope this helps!

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3 years ago

You’ve made the finals of the science Olympics. As one of your tasks you’re given 1.0 g of copper and asked to make a cylindrica

Pani-rosa [81]

Answer:

Length = 2.92 m

Diameter = 0.11 mm

Explanation:

We have $m = dl D \ \ \& \ \ \ R = \frac{\rho l}{A}$ , where:

$l$ is the length

$m = 1.0 g = 1 \times 10^{-3} \ kg\\R = 1.3 \ \Omega\\\rho = 1.7 \times 10^{-8} \Omega m\\d = 8.96 \ g/cm^3 = 8960 kg/m^3$

We divide the first equation by the second equation to get:

$\frac{m}{R} = \frac{d A^2}{\rho}$

$A^2 = \frac{m \rho}{dR} \\\\A^2 = \frac { 1 \times 10^{-3} \times 1.7 \times 10^{-8}}{8960 \times 1.3}\\\\A^2 = 1.5 \times 10^{-15}\\\\ A= 3.8 \times 10^{-8} \ m^2$

Using this Area, we find the diameter of the wire:

$D = \sqrt{\frac{4A}{\pi}}$

$D = \sqrt{\frac{4 \times 3.8 \times 10^{-8} }{\pi}}$

$D = 0.00011 \ m = 1.1 \times 10^ {-4} = 0.11 \ mm$

To find the length, we multiply the two equations stated initially:

$mR = d\rho l^2\\\\l^2 = \frac{mR}{d\rho} \\\l^2 = \frac {1.0 \times 10^{-3} \times 1.3}{8960 \times 1.7\times 10^{-8}}$

$l^2 = 8.534\\l = 2.92 \ m$

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3 years ago

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What was Great Britain’s policy using African Americans during the war

kifflom [539]

Answer:

they were slaves, so they did practically everything anyone didn't do.

Explanation:

btw, which war? or battle?

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3 years ago