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bazaltina [42]
1 year ago
15

Please help will mark Brainliest

Chemistry
1 answer:
Anvisha [2.4K]1 year ago
3 0
  • Lithium is very highly reactive
  • Chlorine is very highly reactive
  • Argon is unreactive.
<h3>What is the chemical reactivity?</h3>

The periodic table sort of makes it possible for us to be able to obtain the reactivity of the elements that are found in the periodic table. This is because, the reactivity of the elements that are in the periodic table generally depends on the group where the element is found in the table.

Lithium and chlorine are highly reactive because they are found in the first and the seventeenth groups of the periodic table which are known for the fact that they are very highly reactive.

Argon is found in group 18 thus it is not a highly reactive element.

Learn more about periodic table:brainly.com/question/11155928

#SPJ1

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Assuming complete dissociation of the solute, how many grams of KNO3 must be added to 275 mL of water to produce a solution that
iragen [17]

Answer:

108.43 grams KNO₃

Explanation:

To solve this problem we use the formula:

  • ΔT = Kf * b * i

Where

  • ΔT is the temperature difference (14.5 K)
  • Kf is the cryoscopic constant (1.86 K·m⁻¹)
  • b is the molality of the solution (moles KNO₃ per kg of water)
  • and<em> i</em> is the van't Hoff factor (2 for KNO₃)

We <u>solve for b</u>:

  • 14.5 K = 1.86 K·m⁻¹ * b * 2
  • b = 3.90 m

Using the given volume of water and its density (aprx. 1 g/mL) we <u>calculate the necessary moles of KNO₃</u>:

  • 275 mL water ≅ 275 g water
  • 275 g /1000 = 0.275 kg
  • moles KNO₃ = molality * kg water = 3.90 * 0.275
  • moles KNO₃ = 1.0725 moles KNO₃

Finally we <u>convert KNO₃ moles to grams</u>, using its molecular weight:

  • 1.0725 moles KNO₃ * 101.103 g/mol = 108.43 grams KNO₃
5 0
3 years ago
Combining 0.350 mol Fe 2 O 3 with excess carbon produced 18.9 g Fe . Fe 2 O 3 + 3 C ⟶ 2 Fe + 3 CO
lapo4ka [179]

Answer:

1. 0.338 moles of Fe

2. 0.700 moles of Fe

3. 48.3%

Explanation:

This is the reaction:

Fe₂O₃ + 3C →  2Fe + 3CO

We were told that we produce 18.9 g of Fe. Let's convert the mass to moles:

18.9 g . 1mol/ 55.85 g = 0.338 moles of Fe

Let's make a rule of three; ratio is 1:2.

1 mol of oxide can produce 2 moles of elemental iron

Then, 0.350 moles must produce (0.350 .2) / 1 = 0.700 moles of Fe

Let's determine the percent yield:

(Yield produced /Theoretical Yield) . 100 = 48.3 %

3 0
4 years ago
Read 2 more answers
A = ε l c. (a) Define the terms in the formula: A = ε l c. (Pick your answers using the letter of the correct definition.)
VladimirAG [237]

Explanation:

Using Beer-Lambert's law :

Formula used :

A=\epsilon \times c\times l

where,

A = absorbance of solution

c = concentration of solution

l = length of the cell

\epsilon = molar absorptivity of this solution

According to question:

A = (C) : absorbance measured by the spectrometer

c = (B) : concentration, in mol/L, of the stock solution from which the sample was made

l = (A): pathlength of light through the cell

ε =  (D) : molar absorptivity, a constant unique to that substance at that wavelength

7 0
3 years ago
Locate the ion that has no change in oxidation number in redox reactions.
natali 33 [55]

a. Spectator ions are the ones that are present but does not enter into the actual chemical  reaction.

b. Na⁺ and NO₃⁻ ions are spectator ions involved in this above mentioned reaction

<u>Explanation:</u>

  • In redox reactions, for example reaction of aqueous silver nitrate and aqueous sodium chloride, silver chloride settles down as a precipitate by the addition of Ag⁺ ion from AgNO₃ and Cl⁻ ions from NaCl .
  • The other 2 ions that is NO₃⁻ ion and Na⁺ ion in the reaction do not enter into the reaction and they are called as Spectator ions.

This can be expressed as the following equation,

AgNO₃(aq) + NaCl(aq) →AgCl(s) + NaNO₃

5 0
4 years ago
A sample of o2 gas (2.0 mmol) effused through a pinhole in 5.0 s. it will take __________ s for the same amount of co2 to effuse
s344n2d4d5 [400]
Answer is: 5,9.
Effusion is leakage of gas through a small hole. Gases with a lower molecular mass effuse more speedy than gases with a higher molecular mass. R<span>elative rates of effusion is related to the molecular mass.
</span>M(O₂) = 32g/mol.
M(CO₂) = 44g/mol.
t₁ = 5s.
t₂ = ?
t₂/t₁ = √(M(CO₂)/M(O₂)).
t₂ = 1,17·5s = 5,9s.

8 0
4 years ago
Read 2 more answers
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