(a) The frequency the blackbird hears is 461.15 Hz.
(b) The frequency the blackbird hears after the eagle passes the blackbird is 422.35 Hz.
Given that, velocity of the eagle v₁ = 31 m/s
Frequency of the eagle F₁ = 440 Hz
Velocity of the blackbird v₂ = 16 m/s
Speed of sound v = 343 m/s
(a) The equation for frequency is given as F = f₀ (v-v₂)/(v-v₁)
F = 440 * (343-16)/(343-31) = 440 * 327/312 = 461.15 Hz
(b) The equation for frequency is given as F = f₀ (v+v₂)/(v+v₁)
F = 440 * (343+16)/(343+31) = 440 *359/374 = 422.35 Hz
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