Answer:
The equation that will express this result os
h = 0 = vy t - 1/2 g t^2 so the net height traveled by the bullet is zero
vy t = 1/2 g t^2
vy = 1/2 g t
vy = 1/2 * 9.8 * t you could use -9.8 to indicate vy and g are in different directions
tx = sx/ vx = 46.4 / 471 = .0985 sec time to travel up and down to original height
th = .0985 / 2 = .0493 sec time to reach maximum height
vy = g ty = 9.8 * .0493 sec = .483 m/s initial vertical speed
Sy = vy t - 1/2 g t^2 = .483 * .0493 - 1.2 9.8 (.0493^^2)
Sy = .0238 - 4.9 ( .0493)^2 = .0238 - .0119 = .0119 m
Height to which bullet will rise - if the gun is aimed at this height then in .0985 seconds the bullet will fall to zero height
Check: .483 / 9.8 = .0493 time to reach zero vertical speed
total travel time = 2 * .0493 = .0986 sec
471 * .0986 = 46.4 m total distance traveled by bullet
the third answer is right.
I hope it is helpful for you...
Answer:
Explanation:Capillary action is the ability of a liquid to flow in narrow spaces without the assistance of, ... This article is about the physical phenomenon. ... If the diameter of the tube is sufficiently small, then the combination of surface tension (which is caused by cohesion ... They derived the Young–Laplace equation of capillary action.
