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Anuta_ua [19.1K]
3 years ago
7

Find three consecutive even integers such that the sum

Physics
1 answer:
SIZIF [17.4K]3 years ago
8 0

Answer:Hi, Sam!

Okay, so let's call the 3 consecutive even integers, X, X + 2 , X +4

So the sum of the smaller two (X +X + 2) = X + 4 +6

2X +2 = X + 10

X = 8

Therefore,

X = 8

X + 2 = 10

X + 4 + 12

These are your integers

Explanation:

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A tennis player practices against a wall, hitting a 0.1 kg ball towards the
pantera1 [17]

Answer: 80 Newton

Explanation:

Initial velocity of ball = +20 m/s.

Final velocity of ball = -20 m/s

Mass of ball = 0.1kg

Time taken = 0.05 seconds

Average force = (Change in momentum of moving ball / Time taken)

Since, change in momentum = Mass (final velocity - initial velocity)

Change in momentum =0.1 x (-20 - (+20))

= 0.1 x (-20-20)

= 0.1 x (-40)

= -4.0 kgm/s

Then, put -4.0 kgm/s in the equation of force when Average Force = (Change in momentum / Time taken)

= (-4.0kgm/s / 0.05 seconds)

= 80Newton (note that the negative sign does not reflect on the magnitude of force)

Thus, the average force exerted on the ball is 80N

3 0
3 years ago
1 poir
djverab [1.8K]

Answer:

D) 735 J(oules)

Explanation:

Work is defined as force * distance

Force is defined as mass * acceleration

Given a mass of 15 kg and a gravitational acceleration of 9.8 m/s² since the box is being lifted up, the force being applied to the box is 15 kg * 9.8 m/s² = 147 N

Since the distance is 5 meters, the work done is 147 N * 5 m = 735 N/m = 735 J, making D the correct answer.

4 0
3 years ago
If the number of homes with a pet dog is equal to 250, how many total homes are repersented by the chart?
scoray [572]
500 because 250 x 2 = 500
3 0
4 years ago
Question: How is a triple beam balance used to find mass?1. Observe: The riders have masses of 10 grams (top), 100 grams (middle
ozzi

Answer:

1) For the weight to be correct, the pointer must be below the reference (zero) or in it

2)  mass greater than 300 g leave the pointer below the reference,

3) put weight on the other arms the pointer gets closer to the reference

Explanation:

1) A three-arm scale is used to determine the weight of a body by successive approximations, starting with the arm with the greatest mass (middle), when the pointer is close to zero without going over, weights are placed on the second arm (above ) weight is placed to bring the pointer closer to the reference without going over and when it is used the arm with the lowest mass is used (below) with this one, masses are placed until reaching the reference,

Taking all the jinetillos placed the total weight, the product of the position of the jinetillo by the precision of the arm and then the three values ​​are added.

In the example given, the jinetillo is placed in position 3 of the 100 arm, so the weight is 300 gr.

For the weight to be correct, the pointer must be below the reference (zero) or in it

2) objects with a mass greater than 300 g leave the pointer below the reference, it must be completed with the other two arms to reach the correct weight

3) when you put weight on the other arms the pointer gets closer to the reference

4 0
4 years ago
A 310-g air track cart is traveling at 1.25 m/s and a 260-g cart traveling in the opposite direction at 1.33 m/s. What is the sp
UNO [17]

Answer:

v_{CM}=0.0732\ m/s

Explanation:

given,

mass of the cart 1, m₁ = 310 g

speed of car 1 , v₁ = 1.25 m/s

mass of cart 2, m₂ = 260 g

speed of cart 2, v₂ = -1.33 m/s

speed of center of mass

v_{CM}=\dfrac{m_1v_1 + m_2 v_2}{m_1 + m_2}

v_{CM}=\dfrac{0.31\times 1.25 +0.26\times (-1.33)}{0.31+0.26}

v_{CM}=\dfrac{0.0417}{0.57}

v_{CM}=0.0732\ m/s

Hence, speed of center of mass of the system is equal to 0.0732 m/s

7 0
4 years ago
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