Answer:
Fc=5253
N
Explanation:
Answer:
Fc=5253
N
Explanation:
sequel to the question given, this question would have taken precedence:
"The 86.0 kg pilot does not want the centripetal acceleration to exceed 6.23 times free-fall acceleration. a) Find the minimum radius of the plane’s path. Answer in units of m."
so we derive centripetal acceleration first
ac (centripetal acceleration) = v^2/r
make r the subject of the equation
r= v^2/ac
ac is 6.23*g which is 9.81
v is 101m/s
substituing the parameters into the equation, to get the radius
(101^2)/(6.23*9.81) = 167m
Now for part
( b) there are two forces namely, the centripetal and the weight of the pilot, but the seat is exerting the same force back due to newtons third law.
he net force that maintains circular motion exerted on the pilot by the seat belts, the friction against the seat, and so forth is the centripetal force.
Fc (Centripetal Force) = m*v^2/r
So (86kg* 101^2)/(167) =
Fc=5253
N
We look at the criteria to select a car.
If we are not too rich, we have to bother about fuel efficiency. The mileage in terms
of km per liter or miles per gallon etc.
engine power - whether it is good enough over a slope (steep) that I may encounter
frequently with my family members.
internal space / total external size : or internal space / total price:
We find these numbers. after all , we make use of the internal space on seats.
we have to know its proportion in the total volume of the car.
the axle turning capability, wheel turning ability :
see the minimum radius and span required to turn a car in a U turn.
we have to bother about its pollution, emission level.
height / width ratio, which is important for the balance of the car.
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If we are looking at the economic point of view
monthly benefit/savings of using the car,converted into currency - Loan EMI
