A rocket takes off from Earth's surface, accelerating straight up at 31.2 m/s2. Calculate the normal force (in N) acting on an a
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Answer:
2.83
Explanation:
Kepler's discovered that the square of the orbital period of a planet is proportional to the cube of the semi-major axis of its orbit, that is called Kepler's third law of planet motion and can be expressed as:
(1)
with T the orbital period, M the mass of the sun, G the Cavendish constant and a the semi major axis of the elliptical orbit of the planet. By (1) we can see that orbital period is independent of the mass of the planet and depends of the semi major axis, rearranging (1):
(2)
Because in the right side of the equation (2) we have only constant quantities, that implies the ratio is constant for all the planets orbiting the same sun, so we can said that:
Intensity of sunlight at given position is defined as power received per unit area
so here we can say
area on which photons are received is given as
now we can find the power received due to sunlight
now we can say this power is due to photons that strikes on surface of earth
so here we can say
given here that
so it will strike 2.47 * 10^18 photons on given area per second