A rocket takes off from Earth's surface, accelerating straight up at 31.2 m/s2. Calculate the normal force (in N) acting on an a
1 answer:
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You traveled a distance of 620.075 meters if it takes you 8.5 seconds to stop.
<u>Given the following data:</u>
- Initial velocity, U = 31.3 m/s
- Time, t = 8.5 seconds.
We know that acceleration due to gravity (a) for an object is equal to 9.8 meter per seconds square.
To find the distance traveled, we would use the second equation of motion:
Mathematically, the second equation of motion is given by the formula;
Where:
- S is the distance travelled.
- u is the initial velocity.
- a is the acceleration.
- t is the time measured in seconds.
Substituting the parameters into the formula, we have;
<em>Distance, S</em><em> = </em><em>620.075 meters.</em>
Therefore, you traveled a distance of 620.075 meters if it takes you 8.5 seconds to stop.
Read more: brainly.com/question/8898885
Answer:
mass of the neutron star =3.45185×10^26 Kg
Explanation:
When the neutron star rotates rapidly, a material on its surface to remain in place, the magnitude of the gravitational acceleration on the central material must be equal to magnitude of the centripetal acc. of the rotating star.
That is
M_ns = mass odf the netron star.
G= gravitational constant = 6.67×10^{-11}
R= radius of the star = 18×10^3 m
ω = 10 rev/sec = 20π rads/sec
therefore,
= 3.45185... E26 Kg
= 3.45185×10^26 Kg