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Hitman42 [59]
3 years ago
14

If you run the 100 m track at a velocity of 5.0 m/s, what is the time needed?

Physics
1 answer:
Tresset [83]3 years ago
8 0
100/5= 20, 20 seconds is the time needed.
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Why is density used to determine the identity of matter?
dedylja [7]
 a substance's density is the same at a certain pressure and temperature, and the density of one substance is usually different than another substance.
4 0
2 years ago
QUESTION 7
ryzh [129]

Answer:

<em>The force required is 3,104 N</em>

Explanation:

<u>Force</u>

According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:

F = ma

Where a is the acceleration of the object.

On the other hand, the equations of the Kinematics describe the motion of the object by the equation:

v_f=v_o+at

Where:

vf is the final speed

vo is the initial speed

a is the acceleration

t is the time

Solving for a:

\displaystyle a=\frac{v_f-v_o}{t}

We are given the initial speed as vo=20.4 m/s, the final speed as vf=0 (at rest), and the time taken to stop the car as t=7.4 s. The acceleration is:

\displaystyle a=\frac{0-20.4}{7.4}

a=-2.757\ m/s^2

The acceleration is negative because the car is braking (losing speed). Now compute the force exerted on the car of mass m=1,126 kg:

F = 1,126\ kg * 2.757\ m/s^2

F= 3,104 N

The force required is 3,104 N

6 0
3 years ago
When it orbited the Moon, the Apollo 11 spacecraft’s mass was 14800 kg, and its mean distance from the Moon’s center was 1.79877
abruzzese [7]

Answer:

Explanation:

If M be mass of moon and m be mass of spacecraft

potential energy of moon -spacecraft system

= - G M m / R where R is radius of orbit of spacecraft

kinetic energy of spacecraft in the orbit

= 1/2 m v² = GMm / 2R

Total energy of spacecraft

=  GMm / 2R  - G M m / R

= - GMm / 2R

for spacecraft to leave the orbit,  energy required

= GMm / 2R

= 6.67259 x 10⁻¹¹ x  7.36 x 10²² x 14800 / (2 x 1.79877 x 10⁶)

= 202035.8 x 10⁵ J .

3 0
3 years ago
Geologists have divided rocks into three different categories based on ______
luda_lava [24]
How they are formed
3 0
3 years ago
a kid is flying a kite 58 meters above the level ground. a small lead sphere is dropped from the kite. calculate the amount of t
Fynjy0 [20]

This is the formula you need to memorize:  

D = 1/2 · a · T²

Distance = (1/2) · (acceleration) · (Time²)

This formula tells the distance an object falls in any amount of time.

This question tells you the distance (58m), and you know the acceleration (gravity, 9.8 m/s²), so you can use this formula to find the time.

Distance = (1/2) · (acceleration) · (Time²)

58m  =  (1/2) · (9.8 m/s²) · (Time²)

Divide each side by (4.9 m/s²) :  Time²  =  (58/4.9) seconds²

Take the square root of each side:  <em>Time = 3.44 seconds  </em>

6 0
3 years ago
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