Answer:
h≅ 58 m
Explanation:
GIVEN:
mass of rocket M= 62,000 kg
fuel consumption rate = 150 kg/s
velocity of exhaust gases v= 6000 m/s
Now thrust = rate of fuel consumption×velocity of exhaust gases
=6000 × 150 = 900000 N
now to need calculate time t = amount of fuel consumed÷ rate
= 744/150= 4.96 sec
applying newton's law
M×a= thrust - Mg
62000 a=900000- 62000×9.8
acceleration a= 4.71 m/s^2
its height after 744 kg of its total fuel load has been consumed


h= 58.012 m
h≅ 58 m
Answer:
B. 560 J
J. 1.2 m
Explanation:
v = Final velocity = 0
u = Initial velocity = 4 m/s
= Coefficient of friction = 0.7
m = Mass of runner = 70 kg
g = Acceleration due to gravity = 
Kinetic energy is given by

The mechanical energy lost is 560 J
Acceleration is given by

From kinematic equations we get

The runner slides for 1.2 m
Answer:
Explanation:
Voltage = 12 (the two batteries are in series and the voltage adds).
Resistance = 3 ohms
I = V / R
I = 12/3
I = 4 amperes.
None of the answers are the right ones. If there is a fifth one that reads 4 amperes then it is the correct answer.
Answer: It is given that A body weighs 20gf in air and 18. 0gf in water. Hence, the answer X-3 = 7.
I believe A is the correct answer!!