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nataly862011 [7]
1 year ago
4

is work performed when we apply more twist (torque) to change the radius of rotation of the bob? is the net acceleration still d

irected towards the axis of rotation?
Physics
1 answer:
Vladimir [108]1 year ago
7 0

Yes, work is performed as we apply more twist (torque) to change the radius of rotation of the bob. The net acceleration is still directed towards the axis of rotation.

The torque that we add to the system is always perpendicular to the radius of rotation. The torque vector is always tangent to this radius vector, so when we increase the amount of torque applied by twisting harder, we cause a larger angle between torque and radius vectors. This means that there is more work done on the system (since more force was applied), and thus net acceleration towards the axis of rotation must increase.

To learn more about torque visit: brainly.com/question/6855614

#SPJ4

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Answer -
Wooden spoon: thermal insulator
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Plastic spatula: thermal insulator
Steel fork: thermal conductor

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Why do different substances produce electromagnetic waves when they are heated up or energized?
Anit [1.1K]

Answer:

Electromagnetic radiation is made when an atom absorbs energy. The absorbed energy causes one or more electrons to change their locale within the atom. When the electron returns to its original position, an electromagnetic wave is produced. ... These electrons in these atoms are then in a high energy state.

Explanation:

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4 years ago
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Gauss's Law states that the net electric flux, , through any closed surface is proportional to the charge enclosed: . The analog
Natali [406]

The analogous formula for magnetic fields is the Ampere's law.

To find the answer, we need to know about the Ampere's law of magnetism.

<h3>What's Ampere's law of magnetism?</h3>

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<h3>What's is the mathematical expression of Ampere's law?</h3>

Mathematically, Ampere's law is

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Thus, we can conclude that the analogous formula for gauss law is the Ampere's law in magnetism.

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5 0
3 years ago
A competitive diver executes a double somersault with a twist from a platform. Her height above the water t seconds after leavin
GarryVolchara [31]

Answer:

One second

Explanation:

Her height above water as function of time after leaving the board is:

h(t)=-16t^2 +0t+ 16

When she enters the water the height above the board is zero so h(t)=0, using that on (1):

0=-16t^2 +0t+ 16

solving equation for t:

16t^2=16

t^2=1

t=\sqrt{1}=1s

Mathematically there're in fact two possible values for t, -1 and 1 but because we're talking of time negative sign has no physical sense then we only use 1.

7 0
3 years ago
A 0.29 kg particle moves in an xy plane according to x(t) = - 19 + 1 t - 3 t3 and y(t) = 20 + 7 t - 9 t2, with x and y in meters
Artist 52 [7]

Answer:

Part a)

F = 7.76 N

Part b)

\theta = -137.7 degree

Part c)

\theta = -127.7 degree

Explanation:

As we know that acceleration is rate of change in velocity of the object

So here we know that

x = -19 + t - 3t^3

y = 20 + 7t - 9t^2

Part a)

differentiate x and y two times with respect to time to find the acceleration

a_x = \frac{d^2}{dt^2}(-19 + t - 3t^3)

a_x = \frac{d}{dt}(0 +1 - 9t^2)

a_x = -18t

a_y = \frac{d^2}{dt^2}(20 + 7t - 9t^2)

a_y = \frac{d}{dt}(0 +7 - 18t)

a_y = -18

Now the acceleration of the object is given as

\vec a = (-18t)\hat i + (-18)\hat j

at t= 1.1 s we have

\vec a = -19.8 \hat i - 18 \hat j

now the net force of the object is given as

\vec F = m\vec a

\vec F = (0.29 kg)(-19.8 \hat i - 18 \hat j)

\vec F = -5.74 \hat i - 5.22 \hat j

now magnitude of the force will be

F = \sqrt{5.74^2 + 5.22^2} = 7.76 N

Part b)

Direction of the force is given as

tan\theta = \frac{F_y}{F_x}

tan\theta = \frac{-5.22}{-5.74}

\theta = -137.7 degree

Part c)

For velocity of the particle we have

v_x = \frac{dx}[dt}

v_x = (0 +1 - 9t^2)

v_y = \frac{dy}{dt}

v_y = (0 +7 - 18t)

now at t = 1.1 s

\vec v = -9.89\hat i - 12.8 \hat j

now the direction of the velocity is given as

\theta = tan^{-1}(\frac{v_y}{v_x})

\theta = tan^{-1}(\frac{-12.8}{-9.89})

\theta = -127.7 degree

7 0
3 years ago
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