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baherus [9]
3 years ago
10

Sometimes the tar of a newly paved road gets sticky on a very hot summer day. What causes this?

Physics
1 answer:
Ksivusya [100]3 years ago
6 0
I’m pretty sure it is caused by the heat of the sun warming it up back into its original state of tar
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Joe balances a stationary coin on the the tip of his finger 20 cm from the top of the table. How much work is Joe doing?
adell [148]

The work done by Joe is 0 J.

<u>Explanation</u>:

When a force is applied to an object, there will be a movement because of the applied force to a certain distance. This transfer of energy when a force is applied to an object that tends to move the object is known as work done.

The energy is transferred from one state to another and the stored energy is equal to the work done.

                                 W = F . D

where F represents the force in newton,  

          D represents the distance or displacement of an object.

Force = 0 N,   D = 20 cm = 0.20 m

                                 W = 0 \times 0.20 = 0 J.

Hence the work done by Joe is 0 J.

7 0
2 years ago
Help asapp!!!!!!!!!!!!!!
IRINA_888 [86]
Sorry don’t know this one
3 0
3 years ago
On a perfect fall day, you are hovering at low altitude in a hot-air balloon, accelerated neither upward nor downward. The total
Stella [2.4K]

Explanation:

Since the balloon is not accelerating means that the net force on the balloon is zero. This implies that the weight of balloon must be equal to the buoyant force on balloon.

Hence, the buoyant force equals the weight of air displaced by the balloon, also 20,000 N.

Weight of the air displaced = density of air × volume

The density of air at 1 atm pressure and 20º C is 1.2 kg/m³  

the volume V = 20,000/(1.2×9.8) =  1700 m³

3 0
2 years ago
The weights in atwoods machine, starting at rest, attain a velocity of 2ft/sec in one sec. Find the ratio of the masses
Orlov [11]
Refer to the figure shown below.
Let m₁ and m₂ e the two masses.
Let a = the acceleration.
Let T =  tension over the frictionless pulley.

Write the equations of motion.
m₂g - T = m₂a            (1)
T - m₁g = m₁a            (2)

Add equations (1) and (2).
m₂g - T + T - m₁g = (m₁ + m₂)a
(m₂ - m₁)g = (m₁ + m₂)a

Divide through by m₁.
(m₂/m₁ - 1)g = (1 + m₂/m₁)a

Define r = m₂/m₁ as the ratio of the two masses. Then
(r - 1)g = (1 +r)a
r(g-a) = a + g
r = (g - a)/(g + a)

With  = 2 ft/s from rest, the acceleration is
a = 2/32.2 = 0.062 ft/s²
Therefore
r = (32.2 - 0.062)/(32.2 + 0.062) = 0.9962

Answer:
The ratio of masses is 0.9962 (heavier mass divided by the lighter mass).

8 0
3 years ago
4. A car accelerating at 60 meters/second is hit in an accident by a bus. The net force exerted on
Licemer1 [7]

Answer:

500kg

Explanation:

mass = newtons/force divided by the acceleration rate

m = 30,000/60

m = 500

3 0
2 years ago
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