We are given the mass of an <span>aluminum sculpture which is 145 kg and a horizontal force equal to 668 Newtons. The coefficient of friction can be determined by dividing the horizontal force by the weight of the object. In this case, 668 N / 145 * 9.8 equal to coeff of friction of 0.47</span>
Is there a question? Because All your doing t explaining a british philosopher to us..
The correct matches are as follows:
<span>Troposphere
A) Layer closest to the Earth where all weather occurs
Mesosphere
</span>C) temperature remains constant as elevation increases<span>
Mesopause
</span>D) temperature remains at a constant zero degrees Celsius as elevation increases<span>
Stratosphere
</span>E) begins between 50-60km and decreases in temperature as elevation increases <span>
Stratopause
</span> B) temperature increases as elevation increases
Hope this answers the question. Have a nice day.
Answer:
4 ohms
Explanation:
R = PL/A
P is resistivity
L is length and is halved
A cross sectional area, the same so
R = P(L/2)/A = 4
