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iris [78.8K]
3 years ago
9

3. A 5 gm/100 ml solution of drug X is stored in a closed test tube

Physics
1 answer:
JulijaS [17]3 years ago
5 0

Answer:

See explanation

Explanation:

The degradation of the drug is a first order process;

Hence;

ln[A] = ln[A]o - kt

Where;

ln[A] = final concentration of the drug

ln[A]o= initial concentration of the drug = 5 gm/100

k= degradation constant = 0.05 day-1

t= time taken

When [A] =[ A]o - 0.5[A]o = 0.5[A]o

ln2.5 = ln5 - 0.05t

ln2.5- ln5 = - 0.05t

t= ln2.5- ln5/-0.05

t= 0.9162 - 1.6094/-0.05

t= 14 days

b) when [A] = [A]o - 0.9[A]o = 0.1[A]o

ln0.5 = ln5 -0.05t

t= ln0.5 - ln5/0.05

t= -0.693 - 1.6094/-0.05

t= 46 days

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4 0
4 years ago
A bomb of mass 4 kg, initially at rest, explodes breaking into two fragments of 1 kg and 3 kg. Which one of the following statem
Kazeer [188]

Answer: The 1 kg fragment will have three times the speed of the 3kg fragment.

Explanation:Here for the bomb, its chemical energy gets converted into the mechanical energy.

According to the law of conservation of momentum, the two bodies will have equal momentum and to satisfy this condition the lighter mass will have the higher velocity.

∵ momentum, p = mass × velocity

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6 0
3 years ago
A passenger train travels 392 mi in the same time that it takes a freight train to travel 322 mi. If the passenger train travels
Yuri [45]

Answer:

Explanation:

Given

distance traveled by  Passenger train is d_1=392\ mi

distance traveled by  Freight train is d_2=322\ mi

Both take same time to travel

suppose speed of freight train is x mph

so speed of passenger train is 20+x mph

we know time=\frac{distance}{speed}

t=\frac{392}{20+x}=\frac{322}{x}

392x=322x+322\times 20

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x=92\ mph

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6 0
3 years ago
If the average speed of a person was 1.2 meters/second, does this mean that their speed was exactly 1.2 meters/second the whole
alexandr1967 [171]

Average speed is defined by the following formula

v = \frac{D}{t}

here

D = total distance that an object move from its initial position to final position

t = total time of the motion

so here we will say that there is no such relation between initial or final speed or we can say maximum or minimum speed of object with average speed of object.

We only need to find the total distance and total time of motion in order to find the average speed

here we can see many examples like let say an object moves with speed v1 for time t1 and then with speed v2 for time t2 then here average speed is given as

d = v_1 t_1 + v_2t_2

since we know that distance covered is product of speed and time

that's why we used above equation for finding total distance

now the average speed will be

v_{avg} = \frac{v_1t_1 + v_2 t_2}{t_1 + t_2}

so this is how we can find the average speed for above motion

so average speed is always between maximum and minimum speed any value in-between.

It is neither the maximum value nor it is minimum value

7 0
3 years ago
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