Answer:
P' = 4 P
Therefore, the power dissipated by the circuit will becomes four times of its initial value.
Explanation:
The power dissipation by an electrical circuit is given by the following formula:
Power Dissipation = (Voltage)(Current)
P = VI
but, from Ohm's Law, we know that:
Voltage = (Current)(Resistance)
V = IR
Substituting this in formula of power:
P = (IR)(I)
P = I²R ---------------- equation 1
Now, if we double the current , then the power dissipated by that circuit will be:
P' = I'²R
where,
I' = 2 I
Therefore,
P' = (2 I)²R
P' = 4 I²R
using equation 1
<u>P' = 4 P</u>
<u>Therefore, the power dissipated by the circuit will becomes four times of its initial value.</u>
The answer is C. Hope it helps
Answer:
Explanation:
a )
moment of inertia of hollow ball
= 2 / 3 mR² , m is mass and R is radius of the ball
= 2 / 3 x 120 x .5²
= 20 kg m²
b )
5 rpm = 5 / 60 rps
n = .0833
angular velocity ω = 2πn= 2 x 3.14 x .0833= .523 rad /s
angular acceleration = increase in angular velocity / time
= .523 - 0 / 20
α = .02615 rad /s²
c )
Torque = moment of inertia x angular acceleration
= 20 x .02615
= .523 Nm
d )
θ = 1/2 α t²
= .5 x .02615 x 20²
= 5.23
2π n = 5.23 where n is required number
n = .83
Crust sitting on top of Milton rock of the mantle
