What was the main aim behind Wegener's continental drift theory?

Physics

1 answer:

Aleks [24]3 years ago

8 0

D.all of the above is the answer for this question

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A uniform pole AB of weight 5w and length 8a is suspended horizontally by tho strings attached to it at C and D where AC=DB=a. A

luda_lava [24]

Moment about D=0 or,T1*6a-5w*3a-9w*2a=0 T2+T1=5w+9w

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3 years ago

Which physical property is best measured using only a balance?

Step2247 [10]

The answer is C-Mass

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2 years ago

A negative ion is (larger/smaller) than its parent atom

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Its larger and if u where wondering to positive ions are smaller

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3 years ago

Two forces act in opposite directions on a wood block. What will happen if the forces are unbalanced?

worty [1.4K]

Answer:

Explanation:

If two unequal forces act in opposite directions, one larger force must cancel out the smaller force,

leaving the net force to be some number in one direction.

Take for example a game of tug-of-war; there are two OPPOSITE forces (groups of people) acting on the rope, one force is pulling with a force in the negative direction while the other force is pulling in the positive direction.

If the forces on the rope were unequal, then the stronger force (group) will pull everything in their direction.

The same will happen on two unequal forces of opposite directions acting on a wooden block. Therefore, since the resultant force will have a non-zero magnitude and direction, there will be a change in the block's motion and position.

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3 years ago

A World War II bomber flies horizontally over level terrain, with a speed of 287 m/s relative to the ground and at an altitude o

Scorpion4ik [409]

Answer: 7.38 km

Explanation: The attachment shows the illustration diagram for the question.

The range of the bomb's motion as obtained from the equations of motion,

H = u(y) t + 0.5g(t^2)

U(y) = initial vertical component of velocity = 0 m/s

That means t = √(2H/g)

The horizontal distance covered, R,

R = u(x) t = u(x) √(2H/g)

Where u(x) = the initial horizontal component of the bomb's velocity = 287 m/s, H = vertical height at which the bomb was thrown = 3.24 km = 3240 m, g = acceleration due to gravity = 9.8 m/s2

R = 287 √(2×3240/9.8) = 7380 m = 7.38 km

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3 years ago