I didn't get all the part with the tiles, but here's the general answer:
given a polynomial
we have that 
is a factor of 
if and only if k is a root of , i.e. if
So, given the polynomial
We can check if 
is a factor by evaluating 
:
So, is not a factor.
Similarly, we can evaluate 
to check if 
are factors:
So, only 
is a factor of 
a square number has and odd amount of numbers but 5to the power of 9 has an even amount of numbers
5×5×5×5×5×5×5×5×5
Answer:
28
Step-by-step explanation:
16−(−12)
=16−(−12)
=16+12
=28
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28 is your answer
(Hope it helps)
Select Is a Function or Is not a Function to correctly classify each relation.
<span><span>Title Is a Function Is not a Function</span><span><span><span><span>{<span><span>(<span>3, 7</span>)</span>,<span>(<span>3, 6</span>)</span>,<span>(<span>5, 4</span>)</span>,<span>(<span>4, 7</span>)</span></span>}</span></span>
</span><span><span><span>{<span><span>(<span>1, 5</span>)</span>,<span>(<span>3, 5</span>)</span>,<span>(<span>4, 6</span>)</span>,<span>(<span>6, 4</span>)</span></span>}</span></span>
</span><span><span><span>{<span><span>(<span>2, 3</span>)</span>,<span>(<span>4, 2</span>)</span>,<span>(<span>4, 6</span>)</span>,<span>(<span>5, 8</span>)</span></span>}</span></span>
</span><span><span><span>{<span><span>(<span>0, 4</span>)</span>,<span>(<span>3, 2</span>)</span>,<span>(<span>4, 2</span>)</span>,<span>(<span>6, 5</span>)</span></span>}</span></span>
</span></span></span>
Answer:
2 to 3 in simplest form
Step-by-step explanation:
