All categories

1 year ago

How does the Army Corps of engineers affect agriculture

Engineering

1 answer:

cricket20 [7]1 year ago

3 0

Answer:

Corps regulators now send threatening letters to farmers who switch from one crop to another, such as rice to orchards, or perform routine plowing.

Explanation:

The Corps says the farmers can be performing a “land-use” change that suddenly puts a farm under Corps jurisdiction. It is getting harder and harder, and in legal terms more dangerous, to be an American farmer these days, thanks to the aggressive behavior of the federal Environmental Protection Agency (EPA) and the U.S. Army Corps of Engineers. Increasingly, those regulations are changing at the arbitrary say-so of the Corps regulators who implement the EPA’s regulations on the ground, even though most practices followed by American farmers have been exempted from CWA prohibitions since it was written in 1977.

You might be interested in

Let m be an integer in the set {0,1,2,3,4,5,6,7,8, 9}, and consider the following problem: determine m by asking 3-way questions

Svetlanka [38]

Answer:

Take any algorithm if that algorithm solves this problem it can be represented as a ternary decision tree. Therefore each question has at most three answers.

There are ten possible verdicts, the height of such kind of tree should satisfy

ℎ >= ⌈log3(10)⌉ = 3

Hence no such algorithm can ask less than three questions in the worst case.

---

Each and every internal node represents a question asking whether m belongs to one of three possible subset of {0, 1, 2, 3, 4, 5, 6, 7, 8, 9} or not

For example 0123|456|789 represented the questionDoes “m: belongs to {0, 1, 2, 3}, to {4, 5, 6}, or to {7, 8, 9}?"

Verdicts are placed in brackets "[ ]"

Explanation:

decision tree is attached below

5 0

3 years ago

Using data in Appendix A ,calculate the number of atoms in 1 tonne of iron

maksim [4K]

<h2>Answer:</h2>

$1.0783*10^{28}(atoms).$

<h2>Explanation:</h2>

<em>Since I don't have access to "Appendix A", I'll solve the problem using data from the periodic table.</em>

<em />

<h3>1. Determine the molar mass of iron.</h3>

<em>According to the periodic table, the molar mass of iron is:</em>

55.845g/mole.

<h3>2. Convert 1 tonne to grams.</h3>

$1(tonne)*1000=1000kg\\1000kg*1000=1000000g=10^6g$

<h3>3. Apply rule of 3.</h3>

$55.845g$ ----------- $1 mole$

$10^6g$ ----------- $x$

$x=\frac{10^6*1}{55.845}=17906.7061(moles)$

<h3>4. Determine the amount of atoms.</h3>

<em>Considering that there are, approximately, </em> $6.022*10^{23}$ atoms in a mole of any element, apply another rule of 3.

1 mole --------------------- $6.022*10^{23}(atoms)$

$17906.7061(moles)$ --------------------- x

$x=\frac{17906.7061*6.022*10^{23}}{1}=1.0783*10^{28}$ .

4 0

2 years ago

In which order are the following measuring instruments listed from lowest precision to highest precision:

siniylev [52]

Wouldn’t it be C tho?

6 0

4 years ago

Car B is traveling a distance dd ahead of car A. Both cars are traveling at 60 ft/s when the driver of B suddenly applies the br

vagabundo [1.1K]

Answer:

Explanation:

Using the kinematics equation $v = v_o + a_ct$ to determine the velocity of car B.

where;

$v_o =$ initial velocity

$a_c$ = constant deceleration

Assuming the constant deceleration is = -12 ft/s^2

Also, the kinematic equation that relates to the distance with the time is:

$S = d + v_ot + \dfrac{1}{2}at^2$

Then:

$v_B = 60-12t$

The distance traveled by car B in the given time (t) is expressed as:

$S_B = d + 60 t - \dfrac{1}{2}(12t^2)$

For car A, the needed time (t) to come to rest is:

$v_A = 60 - 18(t-0.75)$

Also, the distance traveled by car A in the given time (t) is expressed as:

$S_A = 60 * 0.75 +60(t-0.75) -\dfrac{1}{2}*18*(t-0.750)^2$

Relating both velocities:

$v_B = v_A$

$60-12t = 60 - 18(t-0.75)$

$60-12t =73.5 - 18t$

$60- 73.5 = - 18t+ 12t$

$-13.5 =-6t$

t = 2.25 s

At t = 2.25s, the required minimum distance can be estimated by equating both distances traveled by both cars

i.e.

$S_B = S_A$

$d + 60 t - \dfrac{1}{2}(12t^2) = 60 * 0.75 +60(t-0.75) -\dfrac{1}{2}*18*(t-0.750)^2$

$d + 60 (2.25) - \dfrac{1}{2}(12*(2.25)^2) = 60 * 0.75 +60((2.25)-0.75) -\dfrac{1}{2}*18*((2.25)-0.750)^2$

d + 104.625 = 114.75

d = 114.75 - 104.625

d = 10.125 ft

3 0

3 years ago

How much power do a capacitor and inductor dissipate? Assume the capacitor/inductor have no parasitic resistance (no resistor in

Mariana [72]

They do in fact heat up while receiving energy.

4 0

3 years ago

How does the Army Corps of engineers affect agriculture ￼

How does the Army Corps of engineers affect agriculture