Answer:
P=- 88.41 KW
Negative sign indicates that power is given to the system.
Explanation:
Given that
P₂=500 KPa
T₂=130°C
V₂=100 m/s
mass flow rate ,m= 0.8 kg/s
Lets take inlet condition for air
T₁=25°C
P₁=100 KPa
V₁=0 m/s
We know that
Heat capacity for air Cp=1.005 KJ/kg.k
We know that for air change in enthalpy only depends only on temperature
Now from first law for open system
W=-110.52 KJ/kg
Shaft power P = m .W
P = -110.52 x 0.8
P=- 88.41 KW
Negative sign indicates that power is given to the system.
Answer:
MRR = 1.984
Explanation:
Given that
Depth of cut ,d=0.105 in
Diameter D= 1 in
Speed V= 105 sfpm
feed f= 0.015 ipr
Now the metal removal rate given as
MRR= 12 f V d
d= depth of cut
V= Speed
f=Feed
MRR= Metal removal rate
By putting the values
MRR= 12 f V d
MRR = 12 x 0.015 x 105 x 0.105
MRR = 1.984
Therefore answer is -
1.944
Answer:
The pseudocode is as follows:
Input SalesAmount
Input CommissionRate
CommissionEarned= SalesAmount * (CommissionRate/100)
Print CommissionEarned
Explanation:
This gets input for SalesAmount
Input SalesAmount
This gets input for CommissionRate
Input CommissionRate
This calculates the CommissionEarned
CommissionEarned= SalesAmount * (CommissionRate/100)
This prints the calculated CommissionEarned
Print CommissionEarned
Answer:
Solar
Explanation:
The Hubble space telescope is a bus-sized satellite powered by huge solar panels.
Answer:
τ = 0.25 lbf/in²
Explanation:
given that the oil viscosity, μ = 2.415 lb/ft-s
gap between plates = 1/4 inches = 1/4*12 = 1/48 ft
recall from newtons law of viscosity;
shear stress τ = μ du/dy =
τ = (2.415 lb/ft-s) (10 ft/s)/(1/48) ft
τ = 1159.2 lb/ft-s²
we know that, 1 slug = 32.174 lb
lb = 1/32.174 slug
∴ τ = 1159.2/32.174 slug/ft-s² = 36 slug/ft-s²
τ = 36 slug/ft-s²
multiply both the numerator and denominator by ft, this gives
τ = 36 slug-ft/ft²-s²
τ = 36 lbf/ft² where 1 slug-ft/s² = 1lbf
since 1 ft = 12 inch = 1 ft² = 12² in² = 144 in²
∴ τ = 36/144 lbf /in² = 0.25 lbf/in²
τ = 0.25 lbf/in²
