Answer:
See answer and picture below
Explanation:
In this case, the key to get an idea of how is the starting ether is with the final product and the empirical formula of the ether.
First, the empirical formula of the ether gives us information of the structure of the ether. This ether could be either an alkene, alkane or cycloalkane.
Alkane cannot be because alkane's formula is CnH(2n+2), so it's either an alkene or cycloalcane (CnH2n).
However, as we can see, it reacts with HI in excess, so, it cannot be an alkene because in this case the acid will react with the double bond of the ether too forming another product. This discart the fact that the ether has a double bond. So it has to be a cycloalkane.
As the innitial structure it's an ether, it should be either a cyclohexane or cyclopentane with a methyl group attached. So, how can we know which of these structures is? well, we can actually do the reaction with both reactants and see which match. In the attached picture you have the answer.
Hope this helps.
Answer:
14 g
Explanation:
First, we have to calculate the partial pressure of N₂. We know that the air is 80% nitrogen by volume, which, for a gas mixture, means that the mole fraction of N₂ is 0.80.
We can calculate the partial pressure of N₂ (pN₂) using the following expression:
pN₂ = P . x(N₂)
where,
P is the total pressure
x(N₂) is the mole fraction of N₂
pN₂ = 1.1 atm . 0.80 = 0.88 atm
Then, we can calculate the moles of N₂ using the ideal gas equation.
Considering that the molar mass of N₂ is 28.01 g/mol, the mass of N₂ is:
Answer:
-1.5 N because 1.5 N would be upwards and -1.5 N would be downwards
The simplest ratio of elements in a molecule is called as Empirical Formula.
For Example,
Empirical formula of Benzene is CH
Empirical formula of Formaldehyde is CH₂O
Calculation of Empirical Formula:
Empirical formula can be calculated from Molecular formula by dividing the molecular formula with such number that all number of elements in molecular formula gets the lowest and simplest number.
Like Benzene Molecular formula is C₆H₆, when it is divided by 6 we get C₁H₁ or simply CH.
So, for acetic acid having molecular formula C₂H₄O₂ we can only divide it with 2 to have the simplest form, i.e.
C₂H₄O₂ ÷ 2 = C₁H₂O₁ or CH₂O
Result:
So the ratio of elements in acetic acid is
C : H : O
1 : 2 : 1
Answer:
If your lab has litmus paper, you can use it to determine your solution's pH. When you place a drop of a solution on the litmus paper, the paper changes color based on the pH of the solution. Once the color changes, you can compare it to the color chart on the paper's package to find the pH.
Explanation:
A solution's pH will be a number between 0 and 14. A solution with a pH of 7 is classified as neutral. If the pH is lower than 7, the solution is acidic. When pH is higher than 7, the solution is basic. These numbers describe the concentration of hydrogen ions in the solution and increase on a negative logarithmic scale.
For example, If Solution A has a pH of 3 and Solution B has a pH of 1, then Solution B has 100 times as many hydrogen ions than A and is therefore 100 times more acidic.