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nekit [7.7K]
3 years ago
9

Why is it useful to group elements based on the way they behave in chemical reactions?

Chemistry
1 answer:
Basile [38]3 years ago
8 0

<em>The elements in a group often look and behave similarly, because they have the same number of electrons in their outermost shell — the face they show to the world. Group 18 elements, on the far right side of the table, for example, have completely full outer shells and rarely participate in chemical reactions.</em>

<em />

<h2><em>Have a nice day </em></h2>
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How many grams of argon would it take to fill a large light bulb with a volume of 0.745 L at STP?
EastWind [94]

Answer:

Mass = 1.33 g

Explanation:

Given data:

Mass of argon required = ?

Volume of bulb = 0.745 L

Temperature and pressure = standard

Solution:

We will calculate the number of moles of argon first.

Formula:

PV = nRT

R = general gas constant = 0.0821 atm.L/mol.K

By putting values,

1 atm ×0.745 L = n × 0.0821 atm.L/mol.K× 273.15 K

0.745 atm. L = n × 22.43 atm.L/mol

n = 0.745 atm. L / 22.43 atm.L/mol

n = 0.0332 mol

Mass of argon:

Mass = number of moles × molar mass

Mass = 0.0332 mol × 39.95 g/mol

Mass = 1.33 g

8 0
3 years ago
How much energy is required to raise the temperature of 10.6 grams of gaseous neon from
Alona [7]

Answer:

Approximately 1.95 \times 10^{2}\; \rm J.

Explanation:

Look up the specific heat of gaseous neon:

c = 1.03 \; \rm J \cdot g^{-1} \cdot K^{-1}.

Calculate the required temperature change:

\Delta T = (37.9 - 20.0)\; \rm K = 17.9\; \rm K.

Let m denote the mass of a sample of specific heat C. Energy required to raise the temperature of this sample by \Delta T:

Q = c \cdot m \cdot \Delta T.

For the neon gas in this question:

  • c = 1.03\; \rm J \cdot g^{-1}\cdot K^{-1}.
  • m = 10.6\; \rm g.
  • \Delta T = (37.9 - 20.0)\; \rm K = 17.9\; \rm K.

Calculate the energy associated with this temperature change:

\begin{aligned}Q &= c \cdot m \cdot \Delta T \\ &= 1.03\; \rm J \cdot g^{-1}\cdot K^{-1} \times 10.6\; \rm g \times 17.9\; \rm K \\ &\approx 1.95 \times 10^{2}\; \rm J\end{aligned}.

3 0
3 years ago
How does carbon dioxide behave differently (its properties) as a gas compared with as a solid?
ankoles [38]
It is effected by diffusion (the power of smell and wind spread) but a solid is not.
4 0
3 years ago
Match each type of learning to the correct definition.
andreev551 [17]

Answer:

conditioning

trial-and-error learning

insight learning

imprinting

the process of associating a stimulus with a good or bad outcome

the process of using prior knowledge to solve a problem

a bond to a individual or object shortly after birth or hatching

the process of performing a behavior more and more skillf

Explanation:

3 0
3 years ago
Is this right:) please tell me
viva [34]

Answer:

I think that:

The tendency of an object to resist changes in motion: inertia

Attractive force:gravity

And everything else is right

Explanation:

I am not a physicist

But I passed physics with an A

4 0
3 years ago
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