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Kobotan [32]
3 years ago
13

What is the missing word. Please Help Me. Thank you!!

Chemistry
2 answers:
atroni [7]3 years ago
8 0
Mixed with CRYOLITE to lower its melting point
Gnoma [55]3 years ago
7 0
Calcium Floride (Caf2)
Hope this helped =D
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Rainbow [258]

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My personal favorite is dragon ball super.

Explanation:

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3 years ago
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Calculate the volume of 38.0 g of carbon dioxide at STP. Enter your answer in the box provided. L
Free_Kalibri [48]

Answer:

19.3 L

Explanation:

V= n × 22.4

where V is volume and n is moles

First, to find the moles of CO2, divide 38.0 by the molecular weight of CO2 which is 44.01

n= m/ MM

n= 38/ 44.01

n= 0.86344012724

V= 0.86344012724 × 22.4

V= 19.3410588502 L

V= 19.3 L

7 0
3 years ago
What type of central-atom orbital hybridization corresponds to each electron-group arrangement:
galina1969 [7]

Tetrahedral arrangement is resulted upon mixing one s and three p atomic orbitals, resulting in 4 hybridized sp^3 orbitals → sp^3 hybridization.

<h3>What is orbital hybridization?</h3>

In the context of valence bond theory, orbital hybridization (or hybridisation) refers to the idea of combining atomic orbitals to create new hybrid orbitals (with energies, forms, etc., distinct from the component atomic orbitals) suited for the pairing of electrons to form chemical bonds.

For instance, the valence-shell s orbital joins with three valence-shell p orbitals to generate four equivalent sp3 mixes that are arranged in a tetrahedral configuration around the carbon atom to connect to four distinct atoms.

Hybrid orbitals are symmetrically arranged in space and are helpful in the explanation of molecular geometry and atomic bonding characteristics. Usually, atomic orbitals with similar energies are combined to form hybrid orbitals.

Learn more about Hybridization

brainly.com/question/22765530

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3 0
2 years ago
Calculate the enthalpy of the formation of butane, C4H10, using the balanced chemical equation and the standard value below:
zavuch27 [327]

Answer:

+125.4 KJmol-1

Explanation:

∆H C4H10(g) = -2877.6kJ/mol

∆H C(s)=-393.5kJ/mol

∆H H2(g) = -285.8

∆H reaction= ∆Hproducts - ∆H reactants

∆H reaction= (-2877.6kJ/mol) - [4(-393.5kJ/mol) +5(-285.8)]

∆H reaction= +125.4 KJmol-1

6 0
3 years ago
True or false, The four units that must always be used when using the ideal gas are 44.0 liters
Bogdan [553]

Answer:

for volume only liters can be used

Explanation:

4 0
3 years ago
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