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IrinaVladis [17]
3 years ago
14

A 135-g sample of a metal requires 2.50kj to change its temperature from 19.5 degrees Celsius to 100.0 degrees Celsius. What is

the specific heat of this metal?
Chemistry
2 answers:
PolarNik [594]3 years ago
7 0
Q = m x c x ΔT

2500 = 0.135 x C x 80.5

2500 = 10.8765 x C

C = 230.043 J/Kg.K

hope this helps
mars1129 [50]3 years ago
5 0

Answer: The specific heat of the metal is 0.23J/g^0C

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed=2.50kJ=2500J

m= mass of substance = 135 g

c = specific heat capacity = ?

Initial temperature = T_i = 19.5°C

Final temperature = T_f  =100.0°C

Change in temperature ,\Delta T=T_f-T_i=(100-19.5)^0C=80.5^0C

Putting in the values, we get:

2500=135\times c\times 80.5^0C

c=0.23J/g^0C

The specific heat of the metal is 0.23J/g^0C

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