Answer:
T1 = 417.48N
T2 = 361.54N
T3 = 208.74N
Explanation:
Using the sin rule to fine the tension in the strings;
Given
amass = 42.6kg
Weight = 42.6 * 9.8 = 417.48N
The third angle will be 180-(60+30)= 90 degrees
Using the sine rule
W/Sin 90 = T3/sin 30 = T2/sin 60
Get T3;
W/Sin 90 = T3/sin 30
417.48/1 = T3/sin30
T3 = 417.48sin30
T3 = 417.48(0.5)
T3 = 208.74N
Also;
W/sin90 = T2/sin 60
417.48/1 = T2/sin60
T2 = 417.48sin60
T2 = 417.48(0.8660)
T2 = 361.54N
The Tension T1 = Weight of the object = 417.48N
I’m not sure but I think it’s D because we don’t have 20,000 years to make observations
Answer:
Change in translational KE is given as

Explanation:
As we know by work energy theorem that work done by all forces is equal to the change in kinetic energy of the system
So here we know that there are two forces acting on the system
So work done by the system of this force is equal to the change in kinetic energy
So we have

So we have

so we have

Answer:
544 J
Explanation:
Potential energy at top = kinetic energy at bottom + work done by friction
PE = KE + W
mgh = ½ mv² + W
W = mgh − ½ mv²
Given m = 18.0 kg, h = 3.40 m, and v = 2.48 m/s:
W = (18.0 kg) (9.8 m/s²) (3.40 m) − ½ (18.0 kg) (2.48 m/s)²
W = 544 J