1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Murljashka [212]
1 year ago
13

Solve for work when

Physics
1 answer:
BlackZzzverrR [31]1 year ago
3 0

So, <u>the value of the work is approximately 84.65 J</u>.

<h2>Introduction</h2>

Hi ! Here I will help you to discuss the subject about work that caused by force in amount value of angle. Work is affected by the force and displacement.

  • If related to the magnitude of the force, the amount of work will be proportional to the magnitude of the applied force. Thats mean, if the value of the force that applied on it is greater, then the value of the work will be greater.
  • If related to the magnitude of shift, the amount of work will be proportional to the magnitude of shift of object. Thats mean, if the value of the shift on it is greater, then the value of the work will be greater.
<h3>Formula Used</h3>

The work done by a moving object can be expressed in the equation:

If the Angle Is Ignored

\boxed{\sf{\bold{W = F \times s}}}

If the Angle Effect on Work

\boxed{\sf{\bold{W = F \times s \times \cos(\theta)}}}

With the following condition:

  • W = work that done by object (J)
  • F = force that applied (N)
  • s = shift or distance (m)
  • \sf{\theta} = angle of elevation (°)

<h3>Solution</h3>

We know that :

  • F = force that applied = \sf{1.41 \times 10^4} N
  • s = shift or distance = 84.9 m
  • \sf{\theta} = angle of elevation = 45°

What was asked ?

  • W = work that done by object = ... J

Step by step :

\sf{W = F \times s \times \cos(\theta)}

\sf{W = (1.41 \cdot 10^4) \times 84.9 \times \cos(45^o)}

\sf{W = (1.41 \cdot 10^4) \times 84.9 \times \frac{\sqrt{2}}{2}}

\sf{W = 119.709 \times \frac{\sqrt{2}}{2}}

\sf{W = 59.8545 \sqrt{2}}

\boxed{\sf{W \approx 84.65 \: J}}

<h3>Conclusion</h3>

So, the value of the work is approximately 84.65 J.

You might be interested in
A 42.6kg lamp is hanging from wires as shown in figure.The ring has negligible mass. Find tensionsT1, T2,T3 if the object is in
IRISSAK [1]

Answer:

T1 = 417.48N

T2 = 361.54N

T3 = 208.74N

Explanation:

Using the sin rule to fine the tension in the strings;

Given

amass = 42.6kg

Weight = 42.6 * 9.8 = 417.48N

The third angle will be 180-(60+30)= 90 degrees

Using the sine rule

W/Sin 90 = T3/sin 30 = T2/sin 60

Get T3;

W/Sin 90 = T3/sin 30

417.48/1 = T3/sin30

T3 = 417.48sin30

T3 = 417.48(0.5)

T3 = 208.74N

Also;

W/sin90 = T2/sin 60

417.48/1 = T2/sin60

T2 = 417.48sin60

T2 = 417.48(0.8660)

T2 = 361.54N

The Tension T1 = Weight of the object = 417.48N

8 0
3 years ago
Diego hypothesizes that the Earth wobbles on its axis in a pattern that is repeated every 20,000 years.
vichka [17]
I’m not sure but I think it’s D because we don’t have 20,000 years to make observations
5 0
3 years ago
Read 2 more answers
A string is wrapped around a uniform disk of mass M and radius R. Attached to
pav-90 [236]

Answer:

Change in translational KE is given as

\Delta k = FL + (4m + M)gh - \frac{1}{4}MR^2\omega^2 - 2mb^2\omega^2

Explanation:

As we know by work energy theorem that work done by all forces is equal to the change in kinetic energy of the system

So here we know that there are two forces acting on the system

So work done by the system of this force is equal to the change in kinetic energy

So we have

W = FL + (4m + M)gh

So we have

FL + (4m + M)gh = \Delta K + \frac{1}{2}(\frac{1}{2}MR^2 + 4mb^2)\omega^2

so we have

\Delta k = FL + (4m + M)gh - \frac{1}{4}MR^2\omega^2 - 2mb^2\omega^2

8 0
3 years ago
Which of the following decrease when an object becomes colder?
il63 [147K]
I think the answer b
6 0
3 years ago
A 18.0 kg child descends a slide 3.40 m high and reaches the bottom with a speed of 2.48 m/s. How much thermal energy due to fri
Rudik [331]

Answer:

544 J

Explanation:

Potential energy at top = kinetic energy at bottom + work done by friction

PE = KE + W

mgh = ½ mv² + W

W = mgh − ½ mv²

Given m = 18.0 kg, h = 3.40 m, and v = 2.48 m/s:

W = (18.0 kg) (9.8 m/s²) (3.40 m) − ½ (18.0 kg) (2.48 m/s)²

W = 544 J

4 0
3 years ago
Other questions:
  • When you close the switch the needle of the voltmeter moves indicating that a flow of electrons is passing through the cell what
    8·1 answer
  • The lithosphere consists of _______. select one:
    7·1 answer
  • The world record for pole vaulting is 6.15 m. If the pole vaulter's gravitational potential energy is 4942 J, what is his mass?
    7·1 answer
  • Which of the following are examples of a force? (choose as many as apply)
    14·1 answer
  • The current in some DC circuits decays according to the function I=I0e−t/τ, where I is the current at some point in time, I0 is
    7·1 answer
  • A large ebony wood log, totally submerged, is rapidly floating down a flooded river. If the mass of the log is 165 kg, what is t
    9·1 answer
  • The maximum Compton shift in wavelength occurs when a photon isscattered through 180^\circ .
    10·1 answer
  • The largest origin of nonpoint pollution in the united states is A) rain B) industry C) agriculture
    8·1 answer
  • What technique is used by scientists to determine which of several explanations is the best explanation
    9·1 answer
  • Why is a microscope or magnifying glass used to view objects close up instead of moving the object closer to your
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!