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kompoz [17]
3 years ago
5

A horse pulls forward on a carriage with a given force. By Newton's Third Law, the carriage must be pulling on the horse backwar

d with an equal and opposite force. Given this, what explains why the horse and carriage can move forward? Two brown horses pulling wooden carriage Image from Wikimedia Commons, CC BY-SA 2.0 Choose 1 answer: Choose 1 answer: A The cart is rolling on wheels while the horse's hooves have traction with the ground B The forward force of the horse is just big enough to overcome the backward force of the cart and start the cart forward C The cart's force is only in reaction to the horse's force so it does not define direction of movement D There is a brief moment where the horse pulls before the reaction force kicks in E The forward and backward forces are equal, so it actually can't move forward
Physics
1 answer:
olga2289 [7]3 years ago
6 0
The cart's force is only in reaction to the horse's force so it does not define direction of movement.
You might be interested in
If feathers have a density of 0.500 lbs/ft^3, what volume in ft^3 will 8.0 lbs of feathers occupy?
OleMash [197]

Answer:

<em>The volume of the feathers in ft³ = 16 ft³</em>

Explanation:

Density: This can be defined as the ratio of mass of a body to the corresponding volume of that body. The S.I unit of Density is kg/m³

Mathematically it can be expressed as,

D = m/v ................................... Equation 1

making v the subject of the equation above,

v = m/D ............................. Equation 2

Where D = Density of the feathers, m = mass of the feathers, v = volume of the feathers.

Given: D = 0.50 lbs/ft³, m = 8.0 lbs.

Substituting into equation 2

v = 8/0.5

v = 16 ft³

<em>Thus the volume of the feathers in ft³ = 16 ft³</em>

3 0
3 years ago
Two rods, one made of brass and the other made of copper, are joined end to end. The length of the brass section is 0.300 mm and
Marta_Voda [28]

Answer:

(a) T =45.9°C

(b) m = 124kg

Explanation:

In this problem there I'd heat flowing through bars of different composition.

The current flowing through the two bars mus be the same.

The full solution can be found in the attachment below.

8 0
3 years ago
A beam of alpha particles ( q = +2e, mass = 6.64 x 10-27 kg) is accelerated from rest through a potential difference of 1.8 kV.
Mrrafil [7]

Answer:

The magnetic field required required for the beam not to be deflected  is B = 0.0036T

Explanation:

From the question we are told that

    The charge on the particle is q = +2e

    The mass of the particle is  m = 6.64 *10^{-27} kg

    The potential difference is V_a  = 1.8 kV = 1.8 *10^{3} V

    The potential difference between the two parallel plate is  V_b = 120 V

    The separation between the plate is  d = 8 mm =  \frac{8}{1000} =  8*10^{-3}m

   

The Kinetic energy experienced by the beam before entering the region of the parallel plate is equivalent to the potential energy of the beam  after the region having a potential difference of 1.8kV

               KE_b  =  PE_b

Generelly

              KE_b = \frac{1}{2} m v^2

And      PE_b = q V_a

 Equating this two formulas

              \frac{1}{2} mv^2 = q V_a

making v the subject

           v = \sqrt{\frac{q V_a}{2 m} }

Substituting value  

           v = \sqrt{\frac{ 2* 1.602 *10^{-19}  * 1.8 *10^{3}}{2 * 6.64 *10^{-27}} }

           v = 41.65*10^4 m/s

Generally the electric field between the plates is mathematically represented as

                 E = \frac{V_b}{d}  

Substituting value  

                 E = \frac{120}{8*10^{-3}}              

                E = 15 *10^3 NC^{-1}

the magnetic field  is mathematically evaluate    

                     B = \frac{E}{v}

                   B = \frac{15 *10^{3}}{41.65 *10^4}

                    B = 0.0036T

6 0
3 years ago
An electron in a tv picture tube is accelerated through a potential difference of 10 kv before it hits the screen. What is the k
fomenos

Answer:

10,000 eV

Explanation:

Due to the law of conservation of energy, the kinetic energy of the electron at the end of its path is equal to its initial electric potential energy, given by:

U=q\Delta V

where

q is the electron charge

\Delta V is the potential difference

Here we have:

q=1 e is the electron's charged

\Delta V=10 kV=10,000 V is the potential difference

Substituting into the formula, we have

U=(1e)(10,000 V)=10,000 eV

8 0
4 years ago
 If the gauge pressure of a gas is 114 kPa, what is the absolute pressure?
Anastasy [175]

Answer:

D. 214 kPa

Explanation:

The absolute pressure is given by:

p = p_a + p_g

where

p is the absolute pressure

p_a \sim 100 kPa is the atmospheric pressure

p_g is the gauge pressure

In this problem, we have

p_g = 114 kPa

So, the atmospheric pressure is

p = 100 kPa + 114 kPa = 214 kPa

4 0
3 years ago
Read 2 more answers
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