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kompoz [17]
3 years ago
5

A horse pulls forward on a carriage with a given force. By Newton's Third Law, the carriage must be pulling on the horse backwar

d with an equal and opposite force. Given this, what explains why the horse and carriage can move forward? Two brown horses pulling wooden carriage Image from Wikimedia Commons, CC BY-SA 2.0 Choose 1 answer: Choose 1 answer: A The cart is rolling on wheels while the horse's hooves have traction with the ground B The forward force of the horse is just big enough to overcome the backward force of the cart and start the cart forward C The cart's force is only in reaction to the horse's force so it does not define direction of movement D There is a brief moment where the horse pulls before the reaction force kicks in E The forward and backward forces are equal, so it actually can't move forward
Physics
1 answer:
olga2289 [7]3 years ago
6 0
The cart's force is only in reaction to the horse's force so it does not define direction of movement.
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A trolley is moving at constant speed in a friction compensated track. Some plasticine is dropped on the trolley and sticks on i
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Answer:

Since the momentum of the body remains constant ( conserved) the trolley slows down (its velocity reduces) since its mass increases.

5 0
1 year ago
Gravity is a <br><br> A.pushing force<br> B. not a force at all<br> C. pulling force
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Answer:

C

Explanation:

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4 0
2 years ago
People often use simple machines like pulleys, levers, and ramps because they say the machine “makes the work easier.” Which of
dimulka [17.4K]
I think the answer is D.
Hope this help
3 0
2 years ago
Under what conditions can an object have forces acting on it, but its motion does not change ?
Lady_Fox [76]

Answer: An object at rest has zero velocity - and (in the absence of an unbalanced force) will remain with a zero velocity. Such an object will not change its state of motion.

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7 0
2 years ago
1) A record is spinning at the rate of 25 rpm. If a ladybug is sitting 10 cm from the
Sladkaya [172]

<h2>distance = 523 cm</h2>

Explanation:

( a ) The rotational speed of the ladybug = 25 r.p.m = 25/60 r.p.s

= 5/12 rev/sec

( b ) The definition of frequency is the number of rotations per second .

Here the number of rotations per second is 5/12 . Thus frequency = 5/12 Hz

( c ) The tangential speed is v = angular velocity x radius of rotation

The angular velocity ω = 2π x n , where n is the number of rotations per second

Thus angular velocity = 2π x 5/12   = 5π/6 rad/sec

The linear velocity = angular velocity x distance from center of record

Thus tangential speed = 5π/6 x 10 = 25π/3 cm/sec

Angular displacement in 20 sec = ω x t = 5π/6 x 20 = 50π/3 rad

Linear displacement = angular displacement x distance from center of record

= 50π/3 x 10 = 500π/3 = 523 cm

8 0
3 years ago
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