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kompoz [17]
3 years ago
5

A horse pulls forward on a carriage with a given force. By Newton's Third Law, the carriage must be pulling on the horse backwar

d with an equal and opposite force. Given this, what explains why the horse and carriage can move forward? Two brown horses pulling wooden carriage Image from Wikimedia Commons, CC BY-SA 2.0 Choose 1 answer: Choose 1 answer: A The cart is rolling on wheels while the horse's hooves have traction with the ground B The forward force of the horse is just big enough to overcome the backward force of the cart and start the cart forward C The cart's force is only in reaction to the horse's force so it does not define direction of movement D There is a brief moment where the horse pulls before the reaction force kicks in E The forward and backward forces are equal, so it actually can't move forward
Physics
1 answer:
olga2289 [7]3 years ago
6 0
The cart's force is only in reaction to the horse's force so it does not define direction of movement.
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Newton’s second law states that the acceleration of an object is dependent on 1 variable which is the net force
Darya [45]
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3 years ago
Two people play tug of war. The 100-kg person on the left pulls with 1,000 N, and the 70-kg person on the right pulls with 830 N
mezya [45]

Answer:

The  tension on the rope  is  T  =  900 N

Explanation:

From the question we are told that  

     The mass of the person on the left is  m_l  =  100 \ kg

      The force of the person on the left is  F_l  =  1000 \ N

       The mass of the person on the right  is  m_r  =  70 \ kg

       The force of the person on the right is  F_r  =  830 \ N

     

Generally the net force is  mathematically represented as

         F_{Net} =  F_l - F_r

substituting  values

        F_{Net} =  1000-830

       F_{Net} =  170 \ N

Now the acceleration net acceleration of the rope is mathematically evaluated as

        a  =  \frac{F_{net}}{m_I  + m_r  }

substituting  values

     a  =  \frac{170}{100  + 70   }

     a  =  1 \ m/s ^2

The  force m_i *  a) of the person on the left that caused the rope to accelerate by  a  is  mathematically represented as

        m_l * a  =  F_r -T

Where T  is  the tension on the rope  

      substituting values

        100 * 1   =  1000 - T

=>      T  =  900 N

         

4 0
3 years ago
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