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2 years ago

15

According to Boyle’s law, PV= K, what was the volume at the time of the first measurement given the following information? Round

to the nearest mL.
P1=5.42 atm
P2=8.59 atm
V2=527 mL

1 answer:

alexandr402 [8]2 years ago

6 0

Answer:

Iam a learning

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Answer:

The recoil velocity is 0.354 m/s.

Explanation:

Given that,

Mass of hunter = 70 kg

Mass of bullet = 42 g = 0.042 kg

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Using conservation of momentum

$m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}$

Where, $m_{1}$ = mass of hunter

$m_{2}$ = mass of bullet

u = initial velocity

v = recoil velocity

Put the value in the equation

$0+0=70\times v_{1}+0.042\times590$

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A skateboarder starting from rest accelerates down a ramp at 2 m/s for 2 s. What is the final speed of the skateboarder?

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Explanation:

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3 years ago

Can someone help me with this Physics question please?

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Answer:

Explanation:

The formula for this, the easy one, is

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2 years ago

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To develop this problem it is necessary to apply the concepts related to Gravitational Potential Energy.

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Where,

m = Mass

G =Gravitational Universal Constant

R = Distance /Radius

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$U = -\frac{2Gm^2}{R}$

$dU = -\frac{2Gm^2}{R}$

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Therefore replacing we have that,

$\frac{1}{2}mv^2 =\frac{Gm^2}{2R}$

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$v= \sqrt{\frac{Gm}{R}}$

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Therefore

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Answer:

Option A is correct.

(The faster object encounters more resistance)

Explanation:

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Air resistance depends on various factors:

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Shape of the object

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