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3 years ago

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According to Boyle’s law, PV= K, what was the volume at the time of the first measurement given the following information? Round

to the nearest mL.
P1=5.42 atm
P2=8.59 atm
V2=527 mL

1 answer:

alexandr402 [8]3 years ago

6 0

Answer:

Iam a learning

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AJUDEM ME POR FAVOR URGENTE! :(

loris [4]

Link provided in other answer is a SCAM, don’t click on the link !!!!

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3 years ago

Two small plastic spheres are given positive electrical charges. When they are 16.0 cm apart, the repulsive force between them h

Drupady [299]

Answer:

q = 7.542 x 10⁻⁷ C = 754.2 nC

Explanation:

The Coulomb's Law gives the magnitude of the force of attraction or repulsion between two charges:

F = kq₁q₂/r²

where,

F = Force of attraction or repulsion = 0.2 N

k = Coulomb's Constant = 9 x 10⁹ N m²/C²

r = distance between charges = 16 cm = 0.16 m

q₁ = magnitude of 1st charge

q₂ = magnitude of 2nd charge

Since, both charges are said to be equal here.

q₁ = q₂ = q

Therefore,

0.2 N = (9 x 10⁹ N m²/C²)q²/(0.16 m)²

(0.2 N)(0.16 m)²/(9 x 10⁹ N m²/C²) = q²

q = √(5.88 x 10⁻¹³ C²)

<u>q = 7.542 x 10⁻⁷ C = 754.2 nC</u>

7 0

3 years ago

An astronaut holds a rock 100m above the surface of Planet X . The rock is then thrown upward with a speed of 15m/s , as shown i

Butoxors [25]

Answer: $5 m/s^{2}$

Explanation:

The described situation is is related to vertical motion (and free fall). So, we can use the following equation that models what happens with this rock:

$y=y_{o}+V_{o}sin\theta t-\frac{1}{2}gt^{2}$ (1)

Where:

$y=0m$ is the rock's final height

$y_{o}=100 m$ is the rock's initial height

$V_{o}=15 m/s$ is the rock's initial velocity

$\theta=90\°$ is the angle at which the rock was thrown (directly upwards)

$t=10 s$ is the time

$g$ is the acceleration due gravity in Planet X

Then, isolating $g$ and taking into account $sin(90\°)=1$ :

$g=(-\frac{2}{t^{2}})(y-y_{o}-V_{o}t)$ (2)

$g=(-\frac{2}{(10 s)^{2}})(0 m-100 m-(15 m/s)(10 s))$ (3)

Finally:

$g=5 m/s^{2}$ (4) This is the acceleration due gravity in Planet X

7 0

3 years ago

A man plans to use a 2 metre crowbar to lift a rock by putting a pivot 0,8 m from

sp2606 [1]

1. The man will be able to move the rock. See diagram.
   Moment of Man's force : 400 N * 1.2 meter = 480 N-m
   Rock's Weight = 50 Kg * 9.8 m/sec² = 490 Newtons
   Moment of Rock's weight : 490 N * 0.80 meters = 392 N-m

  <em><u> Moment of Man's Force is MORE : 480 N-m > 392 N-m</u></em>
<em><u>   So man will be able to lift the rock.</u></em>

2. Let is look at the diagram - second one.
   Let us assume that the fulcrum (Pivot) is placed at X meters from the rock.
   So moment of Girl's force about Pivot = 200 N * (2 - X) meters = 400 - 200 X
   Moment of Rock's weight = 490 N * X = 490 X

   As the Girl is able to lift the rock, 400 - 200 X > 490 X
   Hence 400 > 200 X + 490 X
      400 > 690 X
   X < 400/690 = 0.58 meters
   <u><em> If the Pivot is placed closer than 0.58 meters or 58 cm to the Rock, then </em></u>
<u><em>   she can lift the rock.</em></u>

4 0

3 years ago

Read 2 more answers

Explain me the inertia of rest ?

sergejj [24]

Hi Pupil Here is Your Answer ::

➡➡➡➡➡➡➡➡➡➡➡➡➡

The tendency of a body to oppose any change in its state of rest is known as inertia of rest.

Example :

1 ) A person standing in a bus Falls backward when the bus suddenly starts moving forward.

Reason》When the bus Moves, the lower part of his party begins to move along with the bus by the upper part of his body continues to remain at rest due to inertia of rest.

That is why, a person Falls backward when the bus suddenly starts.

⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅

Hope this helps . . . . . .

3 0

3 years ago