Answer : The final temperature an the initial pressure of gas is, 273.6 K and 177.6 kPa
Explanation :
First we have to calculate the initial pressure of gas.
As we know that, R-134a is 1,1,1,2-Tetrafluoroethane.
Using ideal gas equation:
where,
P = pressure of gas = ?
V = volume of gas =
T = temperature of gas =
R = gas constant =
w = mass of gas = 10 kg = 10000 g
M = molar mass of R-134a gas = 102.03 g/mole
Now put all the given values in the ideal gas equation, we get:
Thus, the initial pressure of gas is, 177.6 kPa
Now we have to calculate the final temperature of gas.
Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.
or,
where,
= initial pressure of gas = 177.6 kPa
= final pressure of gas = 200 kPa
= initial temperature of gas =
= final temperature of gas = ?
Now put all the given values in the above equation, we get:
Thus, the final temperature an the initial pressure of gas is, 273.6 K and 177.6 kPa