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lisov135 [29]
3 years ago
14

What's true about the elliptical path that the planets follow around the sun? A. A line can be drawn from the planet to the sun

that follows the same curve as the ellipse. B. A vector can be drawn from the center of one planet to the center of an adjacent planet. C. A line can be drawn from the planet to the sun that sweeps out equal areas in equal times. D. A scalar can be measured from the angle that the planet travels relative to the sun's orbit
Physics
1 answer:
Gala2k [10]3 years ago
5 0

Answer:

The answer is C

Explanation:

Just took the test and this is correct on edge, hope this helps :)

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Answer:

HI

Explanation:

its E

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¿Cómo se transforma la energía por eso uso de sistemas amortiguados en una bicicleta?
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No cheating: you’re starring in a movie w/ the last person saved in your camera roll and the last song you listened to is the title.

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8 0
3 years ago
Which change occurs when an atom undergoes decay?
Alina [70]
<span>When an atom undergoes decay its nucleus becomes unstable because it does not have a balance of neurons and protons. This means the atoms try to find a confirmation in which it is stable. In doing so, it is possible that the atom changes its element, and it frees a huge amount of energy in order to balance itself. This is the base of radioactivity.</span>
6 0
3 years ago
One form of energy can be _____ another type of energy.
kotegsom [21]

We can answer this one very quickly.  From the <em>Law of Conservation of Energy</em>, we know that "Energy can't be created or destroyed.".

So that only leaves us one way to complete the sentence in this question:

"One form of energy can be <em>transformed into</em> another type of energy. "  <em>(B)</em>

4 0
3 years ago
Help with 5 and the question below. BRAINLIEST FOR THE CORRECT ANSWER! Urgent Physics help!
krok68 [10]

Sound level at distance of 15 m is given as 20 dB

so intensity at this distance is given as

L = 10 Log\frac{I}{I_0}

20 = 10 Log{I}{10^{-12}}

I_1 = 10^{-10}W/m^2

now if we move closer to some some distance the sound level is now 50 dB

now the intensity is given as

L = 10 Log\frac{I}{I_0}

50 = 10Log\frac{I}{10^{-12}}

I_2 = 10^{-7}W/m^2

now we know that

\frac{I_1}{I_2} = \frac{r_2^2}{r_1^2}

\frac{10^{-10}}{10^{-7}} = \frac{r_2^2}{15^2}

r_2 = 47 cm

so now the distance from friend must be 47 cm

8 0
3 years ago
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