electric potential energy..electrons get the the kinetic energy from the voltage applied across the conductor
Assuming the friction between the skaters and the ice is negligible, the magnitude of Porsha's acceleration is 2.8m/s².
Missing part of the question: determine the magnitude of Porsha's acceleration.
Given the data in the question;
- Mass of Porsha;

- Mass of Zorn;

- Force of Porsha push;

Magnitude of Porsha's acceleration; 
To determine the magnitude of Porsha's acceleration, we use Newton's second laws of motion:

Where m is the mass of the object and a is the acceleration.
We substitute the mass of Porsha and the force he used into the equation
Therefore, assuming the friction between the skaters and the ice is negligible, the magnitude of Porsha's acceleration is 2.8m/s².
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Answer:
b) Rs.901 is the selling price
Explanation:
selling price = cost price+profit percentage/100 x cost price
cost price = 850
profit percentage = 6%
selling price = 850+6/100 x 850 = 901
soln 2
if 100 % = 850
therefore what about 106% = ?
106 x 805/100 = 901
ans = 901
if you need any clarification or more explanation pls do mention on the comment section.i would like to help more
Hope this helps and if it does mark as branliest answer thx
To solve the problem it is necessary to use the concepts related to the calculation of periods by means of a spring constant.
We know that by Hooke's law

Where,
k = Spring constant
x = Displacement
Re-arrange to find k,




Perioricity in an elastic body is defined by

Where,
m = Mass
k = Spring constant


Therefore the period of the oscillations is 0.685s