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Alex73 [517]
3 years ago
13

In the reaction 2H2 + O2 → __H2O, what coefficient should be placed in front of H2O to balance the reaction?

Chemistry
2 answers:
Westkost [7]3 years ago
4 0
I would try the answer A

lys-0071 [83]3 years ago
4 0

<u>Answer:</u> The coefficient '2' must be added in front of H_2O

<u>Explanation:</u>

Every balanced chemical equation follows law of conservation of mass.

A balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on the product side.

The given chemical equation follows:

2H_2+O_2\rightarrow H_2O

<u>On the reactant side:</u>

Number of hydrogen atoms = 4

Number of oxygen atoms = 2

<u>On the product side:</u>

Number of hydrogen atoms = 2

Number of oxygen atoms = 1

We need to add a coefficient '2' in front of H_2O to make the atoms balanced on both sides of the reaction.

Hence, the coefficient '2' must be added in front of H_2O

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3 years ago
An inflatable toy starts with 1.05 moles of air and a volume of 5.17 liters. When fully inflated, the volume is 8.00 liters. If
padilas [110]

Answer:-  1.62 moles

Solution:- At constant temperature and pressure, volume is directly proportional to the moles of the gas.

\frac{V_1}{V_2}=\frac{n_1}{n_2}

from given data, V_1 = 5.17 L, n_1 = 1.05 moles

V_2 = 8.00 L, n_2 = ?

Let's plug in the values in the formula:

\frac{5.17L}{8.00L}=\frac{1.05moles}{n_2}

On cross multiply:

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So, now the toy contains 1.62 moles of the air.


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