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DanielleElmas [232]
1 year ago
13

In the metaphor of the bottle for theory of constraints, which part of the bottle represents the constraint?

Physics
2 answers:
SpyIntel [72]1 year ago
5 0

In the metaphor of the bottle for theory of constraints, the part of the bottle represents the constraint is neck.

<h3>What is metaphor?</h3>

A metaphor is a figure of the speech that describes an object or action in a way that isn’t literally true, but helps explain an idea or make a comparison.

Here are the basics:

A metaphor states that one thing is the another thing. It equates those two things not because they actually are the same, but for the sake of comparison or symbolism and if you take a metaphor literally, it will probably sound very strange (are there actually any sheep, black or otherwise, in your family?). Metaphors are used in the poetry, literature, and anytime someone wants to add some color to their language

The uses of metaphor, and the official definition:

A word or phrase for one thing that is used to refer to the another thing in order to show or suggest that they are similar

An object, activity, or idea that is used as a symbol of the something else

Metaphors are a form of the figurative language, which refers to words or expressions that mean something different from their literal definition. In the case of metaphors, literal interpretation would often be pretty silly.

To know more about phrase visit: brainly.com/question/24271343

#SPJ4

Liono4ka [1.6K]1 year ago
5 0

In the metaphor of the bottle for theory of constraints, the part of the bottle represents the constraint is neck.

<h3>What is metaphor?</h3>

A metaphor is a figure of the speech that describes an object or action in a way that isn’t literally true, but helps explain an idea or make a comparison.

Here are the basics:

A metaphor states that one thing is the another thing. It equates those two things not because they actually are the same, but for the sake of comparison or symbolism and if you take a metaphor literally, it will probably sound very strange (are there actually any sheep, black or otherwise, in your family?). Metaphors are used in the poetry, literature, and anytime someone wants to add some color to their language

The uses of metaphor, and the official definition:

A word or phrase for one thing that is used to refer to the another thing in order to show or suggest that they are similar.

An object, activity, or idea that is used as a symbol of the something else

Metaphors are a form of the figurative language, which refers to words or expressions that mean something different from their literal definition. In the case of metaphors, literal interpretation would often be pretty silly.

To know more about phrase visit: brainly.com/question/24271343

#SPJ4

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A small car with mass of 0.800 kg travels at a constant speed
Alexandra [31]

Answer:

The equation of equilibrium at the top of the vertical circle is:

\Sigma F = - N - m\cdot g = - m \cdot \frac{v^{2}}{R}

The speed experimented by the car is:

\frac{N}{m}+g=\frac{v^{2}}{R}

v = \sqrt{R\cdot (\frac{N}{m}+g) }

v = \sqrt{(5\,m)\cdot (\frac{6\,N}{0.8\,kg} +9.807\,\frac{kg}{m^{2}} )}

v\approx 9.302\,\frac{m}{s}

The equation of equilibrium at the bottom of the vertical circle is:

\Sigma F = N - m\cdot g = m \cdot \frac{v^{2}}{R}

The normal force on the car when it is at the bottom of the track is:

N=m\cdot (\frac{v^{2}}{R}+g )

N = (0.8\,kg)\cdot \left(\frac{(9.302\,\frac{m}{s} )^{2}}{5\,m}+ 9.807\,\frac{m}{s^{2}} \right)

N=21.690\,N

7 0
2 years ago
The intensity of a sound wave at a fixed distance from a speaker vibrating at 1.00 kHz is 0.750 W/m2. (a) Determine the intensit
sveticcg [70]

Answer:

a)   I = 3.63 W / m² , b)   I = 0.750 W / m²

Explanation:

The intensity of a sound wave is given by the relation

         I = P / A = ½ ρ v (2π f s_{max})²

         I = (½ ρ v 4π² s_{max}²) f²

a) with the initial condition let's call the intensity Io

        cte = (½ ρ v 4π² s_{max}²)

         I₀ = cte s² f₀²

        I₀ = cte 10 6

If frequency is increase f = 2.20 10³ Hz

         I = constant (2.20 10³) 2

         I = cte 4.84 10⁶

let's find the relationship of the two quantities

        I / Io = 4.84

        I = 4.84 Io

        I = 4.84 0.750

        I = 3.63 W / m²

b) in this case the frequency is reduced to f = 0.250 10³ Hz and the displacement s = 4 s or

        I = cte (f s)²

        I = constant (0.250 10³ 4)²

 

        I = cte 1 10⁶

         

the relationship

        I / Io = 1

        I = Io

        I = 0.750 W / m²

6 0
2 years ago
a charge of 30. coulombs passes through a 24-ohm resistor in 6.0 seconds. what is the current through the resistor? (1) 1.3 a (3
DochEvi [55]
As I = Q/t (charge/time) the answer is 5a.

30/6 = 5
7 0
3 years ago
Read 2 more answers
How many seconds of space should you keep between you if you're driving a 100 foot truck 30 mph?
Marrrta [24]

Answer:

<em> The space in seconds that will be kept = 2.27 seconds</em>

Explanation:

S = d/t..................... Equation 1

making t the subject of formula in the equation above,

t = d/S.................... Equation 2

Where S = speed, d = distance, t = time.

<em>Conversion: (i)if 1 mph = 0.44704 m/s,</em>

<em>                 then, 30 mph = 30×0.44704    </em>

<em>                = 13.41 m/s</em>

<em>               (ii) If 1 foot = 0.3048 m</em>

<em>            then, 100 foot = 30.48 m.</em>

<em>Given: S = 30 mph = 13.41 m/s, d = 100 foot = 30.48 m</em>

<em>Substituting these values into equation 2</em>

<em>t = 30.48/13.41</em>

<em>t = 2.27 seconds.</em>

<em>Therefore the space in seconds that will be kept = 2.27 seconds</em>

7 0
3 years ago
The plates of a parallel-plate capacitor are 2.50 mm apart, and each carries a charge of magnitude 80.0 nC. The plates are in va
bonufazy [111]

Answer:

10000 V

0.00225988700565 m²

8\times 10^{-12}\ F

Explanation:

E = Electric field = 4\times 10^6\ V/m

d = Gap = 2.5 mm

Q = Charge = 80 nC

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

Potential difference is given by

V=Ed\\\Rightarrow V=4\times 10^6\times 2.5\times 10^{-3}\\\Rightarrow V=10000\ V

The potential difference between the plates is 10000 V

Area is given by

A=\dfrac{Q}{\epsilon_0E}\\\Rightarrow A=\dfrac{80\times 10^{-9}}{8.85\times 10^{-12}\times 4\times 10^6}\\\Rightarrow A=0.00225988700565\ m^2

The area of the plate is 0.00225988700565 m²

Capacitance is given by

C=\dfrac{\epsilon_0A}{d}\\\Rightarrow C=\dfrac{8.85\times 10^{-12}\times 0.00225988700565}{2.5\times 10^{-3}}\\\Rightarrow C=8\times 10^{-12}\ F

The capacitance is 8\times 10^{-12}\ F

4 0
3 years ago
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