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Tpy6a [65]
3 years ago
8

Specific heat capacity​

Physics
1 answer:
Yakvenalex [24]3 years ago
4 0
The amount of heat energy required to raise the temperature of a substance per unit of mass.
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san4es73 [151]
Nine times more (squared speed)
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3 years ago
Hello everyone.Roads are made winding in hilly regions why?Explain​
kicyunya [14]

Answer:

Because winding roads have a gentle slope on hills, so it's easy to climb it than a steepy.

3 0
2 years ago
Why is water pollution a concern if water is continuously cycled through Earth’s systems?
kati45 [8]

Answer:Water pollution is a concern because since it is cycled threw the earths system it effect the earths system in a negative way.

Explanation:

I would wait for someone else to answer just in case I’m wrong.

7 0
3 years ago
The force of the added water produces a torque on the dam. In a simple model, if the torque due to the water were enough to caus
Fittoniya [83]

Answer:

The appropriate response is "\tau=\frac{1}{6} PgLh^3". A further explanation is described below.

Explanation:

The torque (\tau) produced by the force on the dam will be:

⇒  d \tau=XdF

On applying integration both sides, we get

⇒  \tau = \int_{0}^{a}x pgL(h-x)dx

⇒     = pgL\int_{0}^{h}(h-x)dx

⇒     =pgL[\frac{h^3}{2} -\frac{h^3}{3} ]

⇒     =\frac{1}{6} PgLh^3

8 0
2 years ago
The barricade at the end of a subway line has a large spring designed to compress 2.00 m when stopping a 1.10 ✕ 105 kg train mov
Mrac [35]

Answer:

(a) k = 1684.38 N/m = 1.684 KN/m

(b) Vi = 0.105 m/s

(c) F = 1010.62 N = 1.01 KN

Explanation:

(a)

First, we find the deceleration of the car. For that purpose we use 3rd equation of motion:

2as = Vf² - Vi²

a = (Vf² - Vi²)/2s

where,

a = deceleration = ?

Vf = final velocity = 0 m/s (since, train finally stops)

Vi = Initial Velocity = 0.35 m/s

s = distance covered by train before stopping = 2 m

Therefore,

a = [(0 m/s)² - (0.35 m/s)²]/(2)(2 m)

a = 0.0306 m/s²

Now, we calculate the force applied on spring by train:

F = ma

F = (1.1 x 10⁵ kg)(0.0306 m/s²)

F = 3368.75 N

Now, for force constant, we use Hooke's Law:

F = kΔx

where,

k = Force Constant = ?

Δx = Compression = 2 m

Therefore.

3368.75 N = k(2 m)

k = (3368.75 N)/(2 m)

<u>k = 1684.38 N/m = 1.684 KN/m</u>

<u></u>

<u>(</u>c<u>)</u>

Applying Hooke's Law with:

Δx  = 0.6 m

F = (1684.38 N/m)(0.6 m)

<u>F = 1010.62 N = 1.01 KN</u>

<u></u>

(b)

Now, the acceleration required for this force is:

F = ma

1010.62 N = (1.1 kg)a

a = 1010.62 N/1.1 x 10⁵ kg

a = 0.0092 m/s²

Now, we find initial velocity of train by using 3rd equation of motion:

2as = Vf² - Vi²

a = (Vf² - Vi²)/2s

where,

a = deceleration = -0.0092 m/s² (negative sign due to deceleration)

Vf = final velocity = 0 m/s (since, train finally stops)

Vi = Initial Velocity = ?

s = distance covered by train before stopping = 0.6 m

Therefore,

-0.0092 m/s² = [(0 m/s)² - Vi²]/(2)(0.6 m)

Vi = √(0.0092 m/s²)(1.2 m)

<u>Vi = 0.105 m/s</u>

4 0
3 years ago
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