Since the acorn is thrown horizontally, the initial vertical velocity is 0 m/s. Let’s use the following equation to determine the time to fall 10 meters.
<span>d = vi * t + ½ * a * t^2, vi = 0, a = 9.8 </span>
<span>10 = 4.9 * t^2 </span>
<span>t = √(10/4.9) </span>
<span>This is approximately 1.43 seconds. Let’s use the following equation to determine the horizontal distance it moves. </span>
<span>d = v * t = 1.1 * √(10/4.9) </span>
<span>This is approximately 1.57 meters. To determine the horizontal distance between the acorn and squirrel, subtract this distance from 5 meters. </span>
<span>d = 5 – 1.1 * √(10/4.9) </span>
<span>This is approximately 3.83 meters. To catch the acorn, the squirrel must move this distance in the same time as the acorn falls 10 meters. </span>
<span>Average velocity = ([5 – 1.1 * √(10/4.9] ÷ √(10/4.9) = 2.4 m/s </span>
<span>I hope this helps you to understand how to solve this type of problem.</span>
Explanation:
It is given that, in the first trial, the initial velocity is and in the second it is .
The total energy of the system remains constant. So,
....(1)
x is amplitude
It means that the amplitude is directly proportional to velocity. If velcoity increases to four times, then the amplitude also becomes 4 times.
Differentiating equation (1) we get :
Since,
and
So,
It means that the acceleration is also proportional to the amplitude. So, acceleration also becomes 4 times.
Hence, the correct option is (B) "both the amplitude and the maximum acceleration are four times as great"
To solve this problem we will find the net speed, through the two components given. The vertical component will be found through the energy conservation theorem. Finally with speed we will find the momentum as a function of mass and speed. Given the weight we will divide it by the acceleration to find that mass.
The x component is given as
For conservation of energy the vertical component of velocity would be
Here,
m = Mass
g = Gravitational acceleration
h = Height
Replacing we have that the vertical velocity is
The magnitude of this velocity would be
Finally the momentum of the bale would be
Therefore the momentum of the bale the moment it strikes the ground is
Force = mass × accelaration
Force = 0.25Kg × 196 m/s²
Force = 49 Newtons
Answer:
The equilibrant force that will keep the object in equilibrium is;
A. 10 N to the left
Explanation:
The forces acting on the object are;
A 20 Newton force acting to pull the object horizontally to the left
A 30 Newton force acting to pull the object horizontally to the right
For equilibrium, we have;
The sum of forces acting on the object, ∑F = 0
Let '' represent the equilibrant force, with a convention of right = positive, we have;
At equilibrium, ∑F = 30 N - 20 N + = 0
∴ 30 N - 20 N + = 0
10 N = -
∴ = -10 N
With the convention that a force acting to the right = Positive, we have the equilibrant force, = -10 N which is negative, is acting towards the left;
∴ The equilibrant force that will keep the object in equilibrium, = 10 N acting to the left.