Answer:
Minimum uncertainty in velocity of a proton,
Explanation:
It is given that,
A proton is confined to a space 1 fm wide, 
We need to find the minimum uncertainty in its velocity. We know that the Heisenberg Uncertainty principle gives the uncertainty between position and the momentum such that,

Since, p = mv





So, the minimum uncertainty in its velocity is greater than
. Hence, this is the required solution.
There would be 6 electrons placed on the third energy level.
Answer:
25m/s
Steps:
<em> First, The equation v= u + a * t shows us what we need to find, (the finale velocity). </em>
<em />
Second, we substitute the values given:
v= 9m/s + 4m/s2 * 4s
Last, We calculate the values:
Multiply 4m/s2 * 4s = 16m/s
Add 9m/s + 16m/s
<u></u>
<u>Answer: 25m/s</u>
Hope this helps :)
Answer:
The velocity of the student has after throwing the book is 0.0345 m/s.
Explanation:
Given that,
Mass of book =1.25 kg
Combined mass = 112 kg
Velocity of book = 3.61 m/s
Angle = 31°
We need to calculate the magnitude of the velocity of the student has after throwing the book
Using conservation of momentum along horizontal direction


Put the value into the formula


Hence, The velocity of the student has after throwing the book is 0.0345 m/s.
Answer:
Maximum height reached by the ball is 32 meters.
Explanation:
It is given that,
If a baseball is project upwards from the ground level with an initial velocity of 32 feet per second, then it's height is a function of time. The equation is given as :
...........(1)
t is the time taken
s is the height attained as a function of time.
Maximum height achieved can be calculated as :


-16 t + 32 = 0
t = 2 seconds
Put the value of t in equation (1) as :

s = 32 meters
So, the maximum height reached by the ball is 32 meters. Hence, this is the required solution.