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iragen [17]
2 years ago
10

ammonia gas reacts with oxygen gas, o2(g), to produce nitrogen dioxide and water. when 28.5 g of ammonia gas reacts with 83.4 g

of oxygen gas to produce 61.9 g of nitrogen dioxide, what is the percent yield of the reaction?
Chemistry
1 answer:
jolli1 [7]2 years ago
7 0

The percent yield of the reaction between ammonia gas with oxygen gas is 90.52%.

A chemical reaction between ammonia gas (NH3) with oxygen gas (O2)

NH₃ + O₂ → NO₂ + H₂O

The balanced reaction 4NH₃ + 7O₂ → 4NO₂ + 6H₂O

Calculate the number of moles from the reactant

  • Ammonia gas
    Molar mass N = 14 gr/mol
    Molar mass H = 1 gr/mol
    Molar mass NH₃ = 14 + (3 × 1) = 14 + 3 = 17 gr/mol
    mass = 28.5 grams
    n = m ÷ molar mass = 28.5 ÷ 17 = 1.68 mol
  • Oxygen gas
    Molar mass O = 16 gr/mol
    Molar mass O₂ = 16 × 2 = 32 gr/mol
    mass = 83.4 grams
    n = m ÷ molar mass = 83.4 ÷ 32 = 2.61 mol
  • n O₂ ÷ coefficient O₂ = 2.61 ÷ 7 = 0.37
    n NH₃ ÷ coefficient NH₃ = 1.68 ÷ 4 = 0.42
    0.42 > 0.37 it means that the ammonia gas is in excess and the O₂ is limiting.

According to stoichiometry, the number of moles NO₂ with the number of moles O₂ has the ratio with the coefficient in reaction.

  • Theoretically the number moles of NO₂
    n O₂ : n NO₂ = 7 : 4
    2.61 : n NO₂ = 7 : 4
    n NO₂ = 4 x 2.61 : 7 = 1.49 mol
  • The actual number of moles NO₂
    Molar mas NO₂ = 14 + (16 × 2) = 14 + 32 = 46 gr/mol
    n NO₂ = m ÷ molar mass = 61.9 ÷ 46 = 1.35 mol

The percent yield NO₂ is the ratio of the actual number of moles NO₂ with the theoretical number of moles NO₂ times 100%.

P = (1.35 ÷ 1.49) × 100%

P = 0.9052 × 100%

P = 90.52%

Learn more about stoichiometry here: brainly.com/question/13691565

#SPJ4

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Solution.

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The student made a mistake because he did not convert a unit of volume from milliliters to liters. After all, molarity is defined as the number of moles of solute per liter of solution.

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prisoha [69]

Answer: The percentage composition of nitrogen , hydrogen and oxygen is 22.2 % , 1.59 % and 76.2% respectively.

Explanation:

Percentage composition is defined as the ratio of mass of substance to the total mass in terms of percentage.

Percentage composition=\frac{\text {mass of the element}}{\text {Total mass of the substance}}\times 100\%

a) {\text {percentage composition of nitrogen}}=\frac{\text {mass of nitrogen}}{\text {Total mass}}\times 100\%

{\text {percentage composition of nitrogen}}=\frac{9.8g}{9.8+0.7+33.6}\times 100\%=22.2\%

b) {\text {percentage composition of hydrogen}}=\frac{\text {mass of hydrogen}}{\text {Total mass}}\times 100\%

{\text {percentage composition of hydrogen}}=\frac{0.7}{9.8+0.7+33.6}\times 100\%=1.59\%

c) {\text {percentage composition of oxygen}}=\frac{\text {mass of oxygen}}{\text {Total mass}}\times 100\%

{\text {percentage composition of oxygen}}=\frac{33.6}{9.8+0.7+33.6}\times 100\%=76.2\%

The percentage composition of nitrogen , hydrogen and oxygen is 22.2 % , 1.59 % and 76.2% respectively.

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