The molar mass of magnesium (Mg) is 24.30 g/mol. There are 6.02 Times. 1023 atoms in 1 mol.

Determine the oxidation states of the elements in the compounds listed. None of the oxygen-containing compounds are peroxides or

Ahat [919]

Answer :

Oxidation number or oxidation state : It represent the number of electrons lost or gained by the atoms of an element in a compound.

Oxidation numbers are generally written with the sign (+) and (-) first and then the magnitude.

Rules for Oxidation Numbers are :

The oxidation number of a free element is always zero.
The oxidation number of a monatomic ion equals the charge of the ion.
The oxidation number of Hydrogen (H) is +1, but it is -1 in when combined with less electronegative elements.
The oxidation number of oxygen (O) in compounds is usually -2.
The oxidation number of a Group 17 element in a binary compound is -1.
The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.
The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.

Now we have to determine the oxidation state of the elements in the compound.

(a) $H_2SO_4$

Let the oxidation state of 'S' be, 'x'

$2(+1)+x+4(-2)=0\\\\x=+6$

Hence, the oxidation state of 'S' is, (+6)

(b) $Ca(OH)_2$

Let the oxidation state of 'Ca' be, 'x'

$x+2(-2+1)=0\\\\x=+2$

Hence, the oxidation state of 'Ca' is, (+2)

(c) $BrOH$

Let the oxidation state of 'Br' be, 'x'

$x+(-2)+1=0\\\\x=+1$

Hence, the oxidation state of 'Br' is, (+1)

(d) $ClNO_2$

Let the oxidation state of 'N' be, 'x'

$-1+x+2(-2)=0\\\\x=+5$

Hence, the oxidation state of 'N' is, (+5)

(e) $TiCl_4$

Let the oxidation state of 'Ti' be, 'x'

$x+4(-1)=0\\\\x=+4$

Hence, the oxidation state of 'Ti' is, (+4)

(f) $NaH$

Let the oxidation state of 'Na' be, 'x'

$x+(-1)=0\\\\x=+1$

Hence, the oxidation state of 'Na' is, (+1)

4 0

3 years ago

Which of the following is an intensive property of a sample of water

lakkis [162]

Water is a liquid which was made from a gas but if you freeze it you would get a solid but if you leave it in a warm place you would get a liquid so that is the intensive property of a sample of water.<span />

4 0

3 years ago

How are amplitude modulation and frequency modulation techniques similar?

Ivanshal [37]

Answer:

d

Explanation:

7 0

3 years ago

Read 2 more answers

How is good at electron configurations in chemistry?

Paha777 [63]

Try to understand all the rules and laws like:

Aufbau Principle

Hund's rule

Pauli exclusion principle...

Then, you should understand the way in which you can fill the electrons in the orbitals!!

8 0

3 years ago

One photon of a certain type of light has an energy of 7.32x10^-19 J. a.) What is the frequency of this type of light? b.) What

iren [92.7K]

Answer:

f = 1.1041 × 10¹⁵ s⁻¹

λ = 2.72 × 10⁻⁷ m

Explanation:

Given data:

Energy of photon = 7.32 × 10⁻¹⁹ J

Wavelength = ?

Frequency = ?

Solution:

Formula

E = h. f

h = planck's constant = 6.63 × 10⁻³⁴ Kg.m²/s

Now we will put the values in equation

f = E/h

Kg.m²/s² = j

f = 7.32 × 10⁻¹⁹ Kg.m²/s² / 6.63 × 10⁻³⁴ Kg.m²/s

f = 1.1041 × 10¹⁵ s⁻¹

Wavelength of photon.

E = h.c /λ

λ = h. c / E

λ = (6.63 × 10⁻³⁴ Kg.m²/s × 3 × 10⁸ m/s) / 7.32 × 10⁻¹⁹ Kg.m²/s²

λ = 19.89 × 10⁻²⁶ / 7.32 × 10⁻¹⁹ m

λ = 2.72 × 10⁻⁷ m

7 0

3 years ago