Answer:
80.2
Explanation:
we subtract 18.2 from the total percentage which is 100%
Answer:
2100 kPa
Explanation:
The temperature is constant, so the only variables are pressure and volume.
We can use Boyle’s Law.
p₁V₁ = p₂V₂ Divide both sides of the equation by V₂
p₂ = p₁ × V₁/V₂
p₁ = 485 kPa; V₁ = 648 mL
p₂ = ?; V₂ = 0.15 L = 150 mL Calculate p₂
p₂ = 485 × 648/150
p₂ = 2100 kPa
Answer : The activation energy for the reaction is, 51.9 kJ
Explanation :
According to the Arrhenius equation,
or,
![\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7BK_2%7D%7BK_1%7D%29%3D%5Cfrac%7BEa%7D%7B2.303%5Ctimes%20R%7D%5B%5Cfrac%7B1%7D%7BT_1%7D-%5Cfrac%7B1%7D%7BT_2%7D%5D)
where,
= rate constant at 295 K
= rate constant at 305 K = 
Ea = activation energy for the reaction = ?
R = gas constant = 8.314 J/mole.K
= initial temperature = 295 K
= final temperature = 305 K
Now put all the given values in this formula, we get:
![\log (\frac{2K_1}{K_1})=\frac{Ea}{2.303\times 8.314J/mole.K}[\frac{1}{295K}-\frac{1}{305K}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7B2K_1%7D%7BK_1%7D%29%3D%5Cfrac%7BEa%7D%7B2.303%5Ctimes%208.314J%2Fmole.K%7D%5B%5Cfrac%7B1%7D%7B295K%7D-%5Cfrac%7B1%7D%7B305K%7D%5D)
Therefore, the activation energy for the reaction is, 51.9 kJ
C. <span>Regulatory proteins bind to repressor
Both produces certain proteins to break down lactose as a food source.</span>
Answer: O D. It bonds with the added H+ or OH in solution.
Explanation:
