Answer:
Here's what I get
Explanation:
SbCl₃ reacts with water to form slightly soluble antimony oxychloride.
SbCl₃(aq) +H₂O(ℓ) ⇌ SbOCl(s) + 2HCl(aq)
Your observation is an example of Le Châtelier's Principle in action,
The SbCl₃(aq) in your lab has enough HCl added to push the position of equilibrium to the left and keep the SbOCl in solution.
If a few drops of the SbCl₃(aq) were added to 300 mL of water, the solution would turn cloudy. The HCl would be so dilute that the position of equilibrium would lie to the right, and a cloudy precipitate of antimony oxychloride would form.
Reaction is NaHCO3 + HCL = H2CO3 + NaCl
the ratios are 1:1
the 8 moles of HCl are in excess
so if you use 4 moles of NaHCO3 then you will obtain 4 moles of carbonic acid
hope that helps
A link is a part of a chain and an atom is a part of a molecule. It is also a part of a compound. Your answer should be molecule and/or compound
