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Galina-37 [17]
3 years ago
14

In a survey that asked about alcohol use in high school students, which of

Chemistry
2 answers:
Nookie1986 [14]3 years ago
7 0

Answer: B

Explanation: to have a control, and many samples to investigate and cover the differences and anseretics.

tankabanditka [31]3 years ago
3 0
A developing a program to combat alcohol use
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What is the number of moles of solute in a .3 molality solution containing .10 kg of solvent?
denpristay [2]
Concentration can be expressed in different forms: molarity, molality, normality, percentage, part per million and many more. For molality, it is a unit of concentration expressed as moles of solute per kilogram of solvent. Therefore,

0.3 = moles solute/0.10 kg solvent
moles solute = 0.03 moles
4 0
3 years ago
Read 2 more answers
Gamma rays are often used to kill microorganisms in food, in an attempt to make the food safer. Some people contend that this ir
kumpel [21]
<span>While treating food with gamma rays kills microorganism by damaging their DNA, the energy of gamma rays rips off electrons from atoms hence ionizing them (causing free radicals). However, gamma rays do not make the food atoms radioactive. The body has a natural mechanism of riding the body of free radicals. However, large quantities of radicals in the body can cause damage.</span>




7 0
3 years ago
Which of the following is NOT a binary molecular compound?<br> KI <br> H2s<br> CO<br> CIF3
shutvik [7]
I believe KI is not a a binary molecule.
Your welcome
7 0
3 years ago
What is the volume of 88 grams of CO2 gas at STP?
I am Lyosha [343]
! mole of CO2 at STP has a volume of 22.4 liters
88 grams = 2 moles 

so the required volume = 2*22.4 = 44.8 liters
3 0
3 years ago
How many grams of glucose are needed to prepare 400. g of a 2.00% (m/m) glucose solution g?
Dominik [7]
The grams   of glucose  are  needed  to  prepare  400g  of  a 2.00%(m/m)  glucose  solution  g  is  calculated  as  below

=% m/m =mass  of the solute/mass  of  the  solution  x100

let mass of   solute  be represented  by  y
mass  of solution = 400 g
 % (m/m) = 2% = 2/100

 grams  of  glucose  is  therefore =2/100 =  y/400
by cross  multiplication

100y = 800
divide   both side  by  100

y= 8.0 grams



5 0
3 years ago
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