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finlep [7]
1 year ago
12

Crude petroleum is a mixture of many different components. How might one separate out the components to begin the process of ref

ining petroleum
Chemistry
1 answer:
dimaraw [331]1 year ago
8 0

Fractional distillation is used for the refining of crude petroleum.

<h3>How are the components of crude petroleum separated out?</h3>

Fractional distillation is the procedure used to separate crude oil's numerous constituents.

  • A mixture is divided into several components, known as fractions, using fractional distillation.
  • A combination of hydrocarbons makes up crude oil. The crude oil evaporates, and in the fractionating column, its vapors condense at various temperatures.
  • The hydrocarbon molecules in each percent have a comparable number of carbon atoms and a comparable range of boiling points.
  • The mixture is placed above a tall fractionating column that has multiple condensers coming off at various heights.
  • The bottom of the column is warm, while the top is cool. High boiling point compounds condense at the bottom, whereas low boiling point substances condense as they ascend.

Learn more about fractional distillation here:

brainly.com/question/15187318

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Three isotopes of sulfur are sulfur-32, sulfur-33, and sulfur-34. write the complete symbol for each isotope, including the atom
Maurinko [17]
Sulfur is an element in the periodic table that has a chemical symbol of S. This element is the 16th element in periodic table. This means that the atomic number or number of protons in the nucleus of the atom is equal to 16.

The number following the name of the element is the mass number. The following are the complete symbol that are arranged as follows:
 chemical symbol - atomic number - mass number

*Sulfur-32
         S - 16 - 32

*Sulfur-33
        S - 16 - 33

*Sulfur-34
        S - 16 - 34
8 0
3 years ago
Read 2 more answers
Write the formulas for the following ionic compounds: (a) copper bromide (containing the Cu+ ion), (b) manganese oxide (containi
ivann1987 [24]

Answer:The formulas of ionic compounds are:

a)CuBr

b)Mn_2O_3

c)Hg_2I_2

d)Mg_3(PO_4)_2

Explanation:

Formulas for the an ionic compounds is determine by:

Criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

(a) Copper bromide :Given that it contains Cu^+ ion.

Cu^++Br^-\rightarrow CuBr

(b) Manganese oxide : Given that it contains Mn^{3+} ion.

Mn^{3+}+O^{2-}\rightarrow Mn_2O_3

(c)Mercury iodide :Given that it contains Hg_2^{2+}

Hg_2^{2+}+I^-\rightarrow Hg_2I_2

(d) Magnesium phosphate :Given that it contains PO_4^{3-}

Mg^{2+}+PO_4^{3-}\rightarrow Mg_3(PO_4)_2

4 0
3 years ago
The chemical formula of bromomethane is BrCH3. Which correctly describes the number of atoms of each element in bromomethane?
Anit [1.1K]

The number of atoms of each element :

C : 1 atom

H : 3 atoms

Br = 1 atom

<h3>Further explanation</h3>

Given

Bromomethane-CH₃Br

Required

The number of atoms

Solution

The empirical formula is the smallest comparison of atoms of compound forming elements.  

A molecular formula is a formula that shows the number of atomic elements that make up a compound.  

The number of atoms in a compound is generally indicated as a subscript after the atom

C : 1 atom

H : 3 atoms

Br = 1 atom

Total 5 atoms

4 0
3 years ago
A 0.055 mol sample of formaldehyde vapor, CH2O, was placed in a heated 500 mL vessel and some of it decomposed. The reaction is
Elis [28]

Answer:

Kc for this reaction is 0.06825

Explanation:

Step 1: Data given

Number of moles formaldehyde CH2O = 0.055 moles

Volume = 500 mL = 0.500 L

At equilibrium, the CH2O(g) concentration = 0.051 mol

Step 2: The balanced equation

CH2O  <=>  H2 + CO

Step 3: Calculate the initial concentrations

Concentration = moles / volume

[CH2O] = 0.055 moles . 0.500 L

[CH2O] = 0.11 M

[H2] = 0M

[CO] = 0M

Step 4: The concentration at the equilibrium

[CH2O] = 0.11 - X M = 0.051 M

[H2] = XM

[CO] = XM

[CH2O] = 0.11 - X M = 0.051 M

X = 0.11 - 0.051 = 0.059

[H2] = XM = 0.059 M

[CO] = XM = 0.059 M

Step 5: Calculate Kc

Kc = [H2][CO]/[CHO]

Kc = (0.059 * 0.059) / 0.051

Kc = 0.06825

Kc for this reaction is 0.06825

7 0
3 years ago
What can be said about an exothermic reaction with a negative entropy change?.
pashok25 [27]
Spontaneous at low temperatures.
3 0
2 years ago
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