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Leya [2.2K]
1 year ago
8

a certain drug is made from only two ingredients: compound a and compound b. there are milliliters of compound a used for every

milliliters of compound b. if a chemist wants to make milliliters of the drug, how many milliliters of compound a are needed?
Chemistry
1 answer:
Ann [662]1 year ago
8 0

To calculate it using the formulas and learn about drug.

What is drug?

Drugs are by definition chemicals that, when ingested into a living system, influence or modify physiology. Both natural and artificial materials are acceptable. They are low-mass chemical structures, both in terms of atomic and molecular mass.

What is chemist?

At the atomic and molecular levels, chemists look into the characteristics of matter. They gauge proportions and reaction rates to better comprehend new substances and their behavior or to develop novel compounds for use in a variety of real-world scenarios.

Ratio of the compounds A and B are given as

compound A: compound B= 6:5

Now, chemist own to make a drug of 814ml, so we have to distribute these 814 ml in the ratio of 6:5. To make chemically correct drug.

Amount of compound=6/(6+5*814)

=6/11*814=444 ml

∴ Amount of compound a is needed 44 ml.

Therefore, 44 millimeters of a compound are needed.

To learn more about drug from the given link.

brainly.com/question/1189815

#SPJ4

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1) Calculate the number of moles of O2 (g) in 300 cm^3 of gas at 298 k and 1 atm


Ideal gas equation: pV = nRT => n = pV / RT


R = 0.0821 atm*liter/K*mol

V = 300 cm^3 = 0.300 liter

T = 298 K

p = 1 atm


=> n = 1 atm * 0.300 liter / [ (0.0821 atm*liter /K*mol) * 298K] = 0.01226 mol


2) The reaction of a metal with O2(g) to form an ionic compound (with O2- ions) is of the type


X (+) + O2 (g) ---> X2O          or   


2 X(2+) + O2(g) ----> X2O2 = 2XO     or


4X(3+) + 3O2(g) ---> 2X2O3


 
In the first case, 1 mol of metal react with 1 mol of O2(g); in the second case, 2 moles of metal react with 1 mol of O2(g); in the third, 4 moles of X react with 3 moles of O2(g)



So, lets probe those 3 cases.


3) Case 1: 1 mol of metal X / 1 mol O2(g) = x moles / 0.01226 mol

=> x = 0.01226 moles of metal X


Now you can calculate the atomic mass of the hypotethical metal:

1.15 grams / 0.01226 mol = 93.8 g / mol


That does not correspond to any of the metal with valence 1+


So, now probe the case 2.



4) Case 2:


2moles X metal / 1 mol O2(g) = x / 0.01226 mol


=> x = 2 * 0.01226 = 0.02452 mol


And the atomic mass of the metal is: 1.15 g / 0.02452 mol = 46.9 g/mol


That is similar to the atomic mass of titanium which is 47.9 g / mol and whose valece is 2+.


4) Case 3


4 mol meta X / 3 mol O2 = x / 0.01226 => x = 0.01226 * 4 / 3 = 0.01635 


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That does not correspond to any metal.


Conclusion: the identity of the metallic element could be titanium.
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Molecular Formula of Propanoic Acid is....

                                                C₃H₆O₂
Where;

Atomic Mass of C  =  12

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Atomic Mass of O  =  6

Substituting Atomic Masses in molecular formula,

                                                (12)₃ + (1)₆ + (16)₂

                                                   36  +  6  +  32

                                                        74 g/mol

Result:
            
Molecular Mass of Propanoic Acid is 74 g/mol. Structure of Methyl Ethanoate and Propanoic Acid are as follow,

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