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S_A_V [24]
3 years ago
7

what is the number of pairs of electrons that are shared between the nitrogen atoms in a molecule of N2

Chemistry
2 answers:
SOVA2 [1]3 years ago
5 0

Answer:3

Explanation:

The bum above is wrong

lesantik [10]3 years ago
3 0
A Nitrogen got 7 electrons, which means every Nitrogen got 3 pairs of electrons and 1 single electron, ready to be shared.
A second nitrogen come with the same amount of electrons, 3 pairs and 1 single ready to shared. 
The 2 nitrogens put in common their single electrons to create a pair. 
Which means, that 1 pair of electron is shared between the nitrogens in a molecule of N2

Hope this Helps! :)
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ILL GIVE BRAINLIEST
Mice21 [21]

Answer:

Which of the following happens during a lunar eclipse?

Select one:

a. Earth casts a shadow on the moon.

<u>b. The moon casts a shadow on Earth. </u>

c. Earth stops revolving in its orbit.

d. Earth starts revolving around the moon.

Explanation:

7 0
3 years ago
Find the reagent to sythesize 1- phenyl-1-propanol
vova2212 [387]

Answer:

aqueous acid is used as a reagent.  

Explanation:

Addition of Grignard reagent in aldehyde and followed by the acidification give rise to the primary or secondary alcohol. when the formaldehyde is used than the primary alcohol is formed otherwise secondary alcohol is formed.

in this reaction we also use the aqueous acid for the acidification as a reagent. We add aqueous acid when ethanol is present. This is because ethanol is get converted in the presence of aqueous acid into the chloroethane.  

4 0
3 years ago
Calculate the energy required to heat 406.0mg of cyclohexane from 33.5°C to 38.9°C . Assume the specific heat capacity of cycloh
N76 [4]

Answer:

Q = 4.056 J

Explanation:

  • Q = m<em>C</em>ΔT

∴ m = 406.0 mg = 0.406 g

∴ <em>C </em>= 1.85 J/g.K

∴ T1 = 33.5°C ≅ 306.5 K

∴ T2 = 38.9°C = 311.9 K

⇒ ΔT = 311.9 - 306.5 = 5.4 K

⇒ Q = (0.406 g)(1.85 J/gK)(5.4 K)

⇒ Q = 4.056 J

6 0
3 years ago
This figure (Figure 1)shows a container that is sealed at the top
guajiro [1.7K]
I'm pretty sure the answer is 0.833 atm.

Hope I helped! <3

-cara
7 0
3 years ago
For a process Arightwards harpoon over leftwards harpoonB, at 25 °C there is 10% of A at equilibrium while at 75 °C, there is 80
Lostsunrise [7]

This question is describing the following chemical reaction at equilibrium:

A\rightleftharpoons B

And provides the relative amounts of both A and B at 25 °C and 75 °C, this means the equilibrium expressions and equilibrium constants can be written as:

K_1=\frac{90\%}{10\%}=9\\\\K_2=\frac{20\%}{80\%}  =0.25

Thus, by recalling the Van't Hoff's equation, we can write:

ln(K_2/K_1)=-\frac{\Delta H}{R}(\frac{1}{T_2} -\frac{1}{T_1} )

Hence, we solve for the enthalpy change as follows:

\Delta H=\frac{-R*ln(K_2/K_1)}{(\frac{1}{T_2} -\frac{1}{T_1} ) }

Finally, we plug in the numbers to obtain:

\Delta H=\frac{-8.314\frac{J}{mol*K} *ln(0.25/9)}{[\frac{1}{(75+273.15)K} -\frac{1}{(25+273.15)K} ] } \\\\\\\Delta H=4,785.1\frac{J}{mol}

Learn more:

  • brainly.com/question/10038290
  • brainly.com/question/19671384
5 0
3 years ago
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