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Tresset [83]
3 years ago
6

How many moles are in 3.24 x 1020 particles of lead? (show work plz)

Chemistry
1 answer:
lesya [120]3 years ago
7 0
<h3>Answer:</h3>

0.000538 mol Pb

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.24 × 10²⁰ particles Pb (lead)

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                                  \displaystyle 3.24 \cdot 10^{20} \ particles \ Pb(\frac{1 \ mol \ Pb}{6.022 \cdot 10^{23} \ particles \ Pb})
  2. Multiply/Divide:                                                                                               \displaystyle 0.000538 \ mol \ Pb

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

Our final answer is in 3 sig figs, no need to round.

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1.B
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D because t<span>he mass of one mole (molar mass) of helium gas is </span>4.002602 g/mol. 4.002602 * 5=20.01309. Rounded equals 20. So, the answer is D.20 g.
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What percentage of oxygen is attributed fossil fuel combustion
Oxana [17]

Answer:

C. 4%

Explanation:

The answer is 4%

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2 years ago
How do you make a model of something you cannot see?
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You have to imagine it
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02. Using Tables 1 to 3, what pattern do you observe in terms of the phase and number of carbon atoms of the alkanes, alkenes, a
BabaBlast [244]

Hey there mate ;), Im Benjemin and lets solve your question.

★ (Alkanes) : forms single bonds between carbon atoms.

The first four elements are gases and others are liquid in state.

★(Alkenes) : forms double bonds between carbon atoms.

The first three alkenes are gases and rest are liquid.

★ (Alkynes) : forms triple bonds between carbon atoms.

First three are gases and the last one is liquid.

According to boiling point :

The larger structure of the hydrocarbons, the higher the boiling points they have.

In the 3 tables, we can see that the boiling point increases.

5 0
3 years ago
aseous methane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 5.5 g of methane is
maksim [4K]

Answer:

There is 9.6 grams of CO2 produced

Explanation:

Step 1: Data given

Mass of methane = 5.50 grams

Molar mass of methane = 16.04 g/mol

Mass of oxygen = 13.9 grams

Molar mass of oxygen = 32.0 g/mol

Step 2: The reaction

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

Step 3: Calculate number of moles

Moles = mass / molar mass

Moles methane = 5.50 grams / 16.04 g/mol

Moles methane = 0.343 moles

Moles oxygen = 13.9 grams / 32.0 g/mol

Moles oxygen = 0.434 moles

For 1 mol CH4 we need 2 moles O2 to produce 1 mol CO2 and 2 moles H2O

O2 is the limiting reactant. It will completely react (0.434 moles).

There will react 0.434/2 = 0.217 moles CH4

There will remain 0.343-0.217 = 0.126 moles CH4

There will be produced 0.434 moles of H2O and

0.434/2 =0.217 moles of CO2

Step 4: Calculate mass of products

Mass = moles * molar mass

Mass CO2 = 0.217 moles ¨44.01 g/mol

Mass CO2 = 9.6 grams

Mass H2O = 0.434 moles * 18.02

Mass H2O = 7.8 grams

4 0
3 years ago
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