All categories

3 years ago

If the [H+] in a solution is 1 x 10^-1 mol/L, what is the [OH-]? Show your work, please i need help

Chemistry

1 answer:

igor_vitrenko [27]3 years ago

8 0

Answer:

You need to know the following equations:

pH=-log[H⁺]

pOH=-log[OH⁻]

pH+pOH=14

then you can find the pH by using pH=-log(1×10⁻¹)

pH=1

then you can find pOH by doing pOH=14-1

pOH=13

then you can find [OH] by using [OH⁻]=10^(-pOH)

[OH⁻]=1×10⁻¹³mol/L

You could also use the equation Kw=[OH⁻][H⁺] where Kw=10⁻¹⁴

10⁻¹⁴/10⁻¹=10⁻¹³mol/L

mark brainiest??

You might be interested in

A 0.80 L sample of gas has a temperature of 27°C and a pressure of 0.925 atm. How many moles of gas are present?

ololo11 [35]

Answer:

n= 0.03 moles

Explanation:

Using the ideal gas law:

PV=nRT

nRT=PV

n= PV/RT

n: moles

P: pressure in atm

V= volume in L

R= Avogadro's constant = 0.0821

T= Temperature in K => ºC+273.15

n= (0.925 atm)(0.80 L) / (0.0821)(300.15 K)

n= 0.03 moles

6 0

3 years ago

Why the ph of glycine increases when 0.1 M NaOH is added dropwise

shtirl [24]

Answer:

The acid-base reaction produces glycine reduction, and hence the increase of glycine pH.

Explanation:

The glycine is an amino acid with the following chemical formula:

NH₂CH₂COOH

The COOH functional group is what gives the acid properties in the molecule.

Hence, when NaOH is added to glycine an acid-base reaction takes place in which COOH reacts with the NaOH added:

NH₂CH₂COOH + OH⁻ ⇄ NH₂CH₂COO⁻ + H₂O

The glycine concentration starts to shift to its ion form (NH₂CH₂COO⁻) because of the reaction with NaOH, that is why the pH glycine increases when NaOH is added.

Therefore, the acid-base reaction produces glycine reduction, and hence the increase of glycine pH.

I hope it helps you!

7 0

2 years ago

If the container is closed and the ethanol is allowed to reach equilibrium with its vapor, how many grams of liquid ethanol rema

SVETLANKA909090 [29]

Explanation:

Let us assume that the given data is as follows.

V = 3.10 L, T = $19^{o}C$ = (19 + 273)K = 292 K

P = 40 torr (1 atm = 760 torr)

So, P = $\frac{40 torr}{760 torr} \times 1 atm$

= 0.053 atm

n = ?

According to the ideal gas equation, PV = nRT.

Putting the given values into the above equation to calculate the value of n as follows.

PV = nRT

$0.053 atm \times 3.10 L = n \times 0.0821 L atm/mol K \times 292 K$

0.1643 = $n \times 23.97$

n = $6.85 \times 10^{-3}$

It is known that molar mass of ethanol is 46 g/mol. Hence, calculate its mass as follows.

No. of moles = $\frac{mass}{\text{molar mass}}$

$6.85 \times 10^{-3} = \frac{mass}{46 g/mol}$

mass = $315.1 \times 10^{-3}$ g

= 0.315 g

Thus, we can conclude that the mass of liquid ethanol is 0.315 g.

4 0

2 years ago

Predict the precipitate produced by mixing an Al(NO3)3 solution with a NaOH solution. Write the net ionic equation for the react

weqwewe [10]

Al(NO3)3(aq) + 3NaOH(s) --> Al(OH)3 (s) + 3NaNO3 (aq)

The precipitate here is Al(OH)3 (s), since the solid reactant is the precipitate in the aqueous solution. Usually, it is okay to assume in basic chemistry that the transition metal is going to be part of the compound that is the precipitate, especially in an acidic salt and a strong base reaction that we have here.

4 0

3 years ago

Which of the following statements about the carbon cycle is NOT true?

nalin [4]

Answer:

Plants consume carbon through transpiration

Explanation:

In transpiration, plants lose water vapor through the stomata in their leaves. No carbon is involved in transpiration, which has an outbound direction. Nothing can be consumed through the stomata when vapor is going out of the plant. It´s like trying to get in through the exit.

3 0

3 years ago

Read 2 more answers