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Neko [114]
3 years ago
15

815 yd to km (need 3 sig fig)

Chemistry
1 answer:
SpyIntel [72]3 years ago
5 0

<u>Answer:</u> The correct answer is 0.745 km

<u>Explanation:</u>

We are given:

A numerical value of 815 yards

To convert this into kilometers, we use the conversion factor:

1 km = 1093.6 yards

Converting the given value into kilometers, we get:

\Rightarrow 815yd\times \frac{1km}{1093.6yd}=0.745km

Hence, the correct answer is 0.745 km

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Molar mass of O is = 16

Molar mass of O2 = 32

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Answer:

all electrons of the atom

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Bromination occurs on alkene functional groups, but NOT on alkenes found within aromatic functional group, such as the phenyl ri
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4 years ago
Sodium carbonate, Na2CO3(s), can be prepared by heating sodium bicarbonate, NaHCO3(s). 2 NaHCO3(s) Na2CO3(s) + CO2(g) + H2O(g) K
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Step 1: Data given

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Step 3: Calculate the pressure of CO2

Kp = (p(CO2))*(p(H2O))

For 1 mol CO2 we have 1 mol H2O

x = p(CO2) = p(H2O)

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x = 0.48

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3 years ago
Calculate the number of milliliters of 0.666 M Ba(OH)2 required to precipitate all of the Pb2 ions in 163 mL of 0.656 M Pb(NO3)2
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Answer:

161 mL

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First we <u>calculate how many Pb⁺² moles reacted</u>, using the<em> given concentration and volume of the Pb(NO₃)₂ solution</em>:

  • 163 mL * 0.656 M = 107 mmol Pb(NO₃)₂

As<em> 1 millimol of Pb(NO₃)₂ would react with 1 millimol of Ba(OH)₂,</em> to precipitate 107 mmoles of Pb(NO₃)₂ we would require 107 mmoles of Ba(OH)₂.

Using the number of moles and the concentration we can <u>calculate the required number of milliliters</u>:

  • 0.666 M = 107 mmol / x mL
  • x mL = 161 mL
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3 years ago
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