Given:
There are two consecutive odd integers such that the square of the first added to 3 times the second, is 24.
To find:
Part a: Define the variables.
Part b: Set up an equations that can be solved to find the integers.
Part c: Find the integers.
Solution:
Part a:
Let x be the first odd integers. Then next consecutive odd integer is
, because the difference between two consecutive odd integers is 2.
Part b:
Square of first odd integers = 
Three times of second odd integers = 
It is given that the sum of square of first odd integers and three times of second odd integers is 24. So, the required equation is:

Part c:
The equation is:

It can be written as:



Splitting the middle term, we get




-6 is not an odd integer, so
and the first odd integer is 3.
Second odd integer = 
= 
= 
Therefore, the two consecutive odd integers are 3 and 5.
Answer:1
1/6 3/12 2/3
Step-by-step explanation:
3/12 = 2/6
2/3 = 4/6
1/6<2/6<2/3
I think a is (8,-8)
B) (0,8)
Answer:
I'm pretty sure b is the answer
Answer:

Step-by-step explanation:
Treat this the same way you would an equation. Isolate the variable. Add 6 to both sides:

Divide both sides by 5:

The value of x is less than 3.
:Done