Mass of trolley (m):

7. Two bikes travelling in the same direction move at a speed of 30 km/hr. The bikes are separated by a distance of 5 km. What w

Fantom [35]

Answer:

Explanation:

Call the bike on the right A

Call the bike on the left B

The car begins it's time when it passes A

4 minutes later, it passes B.

But B has moved in 4 minutes and that is the key to the problem.

How far has B moved.

t = 4 minutes = 4/60 hours = 1/15 of an hour.

d = ?

rate = 30 km / hr

d = r * t

d = 30 km/hr * 1/15 hours = 2 km

The distance between the bikes is 5 km.

So the car has traveled 5 - 2 = 3 km

d = 3 km

r = ?

t = 4 minutes = 1/15 hour

r = d/t = 3/(1/15)= 3 / 0.066666666 = 45 km/hr.

6 0

3 years ago

A particle with charge 5 . 0- µ C is placed at the corner of a cube. (Physics Help)? A particle with charge 5.0-µC is placed at

Svetradugi [14.3K]

Gauss law states that the electric flux through any closed surface is proportional to the net electric charge inside the surface. This is expressed mathematically in the form of:

Φ = Q / εo

Where,

Φ = the electric flux = unknown (which we have to find for)

Q = the net electric charge = 5.0 µC = 5 E-6 C

εo = the permittivity of free space = a constant value = 8.85 E-12 C^2 / N m^2

Plugging in the values into the equation will result in:

Φ = 5 E-6 C / (8.85 E-12 C^2 / N m^2)

Φ = 564,971.75 Wb = <span>5.6 x 10^5 Wb </span>

6 0

3 years ago

Which statement relates most directly to the second law?

alukav5142 [94]

Statement three i do believe

7 0

3 years ago

Read 2 more answers

Extreme-sports enthusiasts have been known to jump off the top of El Capitan, a sheer granite cliff of height 910 m in Yosemite

german

Answer:

The jumper is in freefall for 12.447 seconds.

Explanation:

Let's start by calculating how far the jumper falls.

Initial height (on cliff) = 910 m

Final height after freefall = 150 m

Distance the jumper falls in freefall = 910 - 150 = 760 m

We can now use the equation of motion below to solve for the time:

$s=u*t+\frac{1}{2} (a*t^2)$

here. acceleration = 9.81 m/s (due to gravity)

initial speed (u) = 0 m/s (because vertical speed is 0 at the start)

and distance (s) = 760 meters (as calculated above)

So for speed we get:

$760=0*t+0.5(9.81*t^2)$

$760=4.905t^2$

t = 12.447 seconds

5 0

3 years ago

A bike and rider together have a mass of 60 kg. If the bike and rider have an acceleration of 2.0 m/s^2, what is the force on th

Mice21 [21]

The net force on the bike and the rider is 120 N

Explanation:

We can solve this problem by applying Newton's second law of motion, which states that:

F = ma

where

F is the net force exerted on an object

m is the mass of the object

a is its acceleration

For the bike and the rider in this problem, we have

m = 60 kg is their combined mass

$a=2.0 m/s^2$ is their acceleration

Therefore, the net force on them is

$F=(60)(2.0)=120 N$

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

8 0

3 years ago