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marishachu [46]
3 years ago
7

Can you please give the real answers! ​

Physics
1 answer:
luda_lava [24]3 years ago
6 0
B is more reccomended but as you define the sum of the C it can be also decent so it can be neither the B or C
You might be interested in
By how many newtons does the weight of a 85.9-kg person lose when he goes from sea level to an altitude of 6.33 km if we neglect
sergejj [24]

Answer:

Weight\ loss=1.6321N

Explanation:

From the question we are told that:

Weight W=85.9kg

Altitude h= 6.33 km

Let

Radius of Earth r=6380km

Gravity g=9.8m/s^2

Generally the equation for Gravity at altitude is mathematically given by

 g_s=9.8(\frac{6380}{6380+6.33})^2

 g_s=9.781m/s^2

Therefore

Weight at sea level

 W_s=9.8*85.9

 W_s=841.82N

Weight at 6.33 altitude

 W_a=9.781*85.9

 W_a=840.2N

Therefore

 Weight loss=W_s-W_b

 Weight loss=841.82-840.2

 Weight loss=1.6321N

3 0
3 years ago
Which of the following is a difference between a mercury barometer and an aneroid barometer?
melomori [17]
They are made of different substances
7 0
3 years ago
MODERN PHYSICS
frosja888 [35]

Answer:

D. n=6 to n=2

Explanation:

Given;

energy of emitted photon, E = 3.02 electron volts

The energy levels of a Hydrogen atom is given as;  E = -E₀ /n²

where;

E₀ is the energy level of an electron in ground state =  -13.6 eV

n is the energy level

From the equation above make n, the subject of the formula;

n² = -E₀ / E

n² = 13.6 eV / 3.02 eV

n² = 4.5

n = √4.5

n = 2

When electron moves from higher energy level to a lower energy level it emits photons;

E = E_0(\frac{1}{n_1^2}-\frac{1}{n_2^2} )\\\\\frac{1}{n_1^2}-\frac{1}{n_2^2} = \frac{E}{E_o} \\\\\frac{1}{4} -\frac{1}{n_2^2} = \frac{3.02}{13.6} \\\\\frac{1}{4} -\frac{1}{n_2^2} =0.222\\\\\frac{1}{n_2^2} = 0.25 - 0.22\\\\\frac{1}{n_2^2} = 0.03\\\\n_2^2 = 33.33\\\\n_2 = \sqrt{33.33} = 6

For a photon to be emitted, electron must move from higher energy level to a lower energy level. The higher energy level is 6 while the lower energy level is 2

Therefore,  The electron energy-level transition is from n = 6 to n = 2

3 0
3 years ago
Electrons (mass m, charge –e) are accelerated from rest through a potential difference V and are then deflected by a magnetic fi
adell [148]

Answer:

r=\dfrac{1}{B}\sqrt{\dfrac{2Vm}{e}}

Explanation:

Let m and e are the mass and charge of an electron. It is accelerated from rest through a potential difference V and are then deflected by a magnetic field that is perpendicular to their velocity. Let v is the velocity of the electron. It can be calculated as :

\dfrac{1}{2}mv^2=eV

v=\sqrt{\dfrac{2eV}{m}}

When the electron enters the magnetic field, the centripetal force is balanced by the magnetic force as :

\dfrac{mv^2}{r}=evB

r=\dfrac{mv}{eB}

or

r=\dfrac{1}{B}\sqrt{\dfrac{2Vm}{e}}

So, the radius of the resulting electron trajectory is \dfrac{1}{B}\sqrt{\dfrac{2Vm}{e}}. Hence, this is the required solution.

8 0
3 years ago
Which is not an example of work being done?
mezya [45]
C. Carrying a backpack to class
7 0
3 years ago
Read 2 more answers
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