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pshichka [43]
3 years ago
8

What is another name for Kepler's Third Law? Select all that apply.

Physics
1 answer:
user100 [1]3 years ago
7 0
It’s is referred to the law of harmony so C
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I<span>n </span>direct current<span> (</span>DC), the electric charge (current<span>) only flows in one direction. Electric charge in </span>alternating current<span> (</span>AC<span>), on the other hand, changes direction periodically. The voltage in </span>AC<span> circuits also periodically reverses because the </span>current<span> changes direction.</span>
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light waves are first transmitted through the ________ at the front of the eye and enter an opening called the ________ before s
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The transmission of light waves is usually done through cornea of the eyes, then move through another opening which is regarded as pupil before it will get to the retina.

  • Light waves can be regarded as moving energy which contains microscopic particles known as photons.
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  • Light will move through the (cornea) which is situated at the front area of the eyes into lens.
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2 years ago
Smaller mammals use proportionately more energy than larger mammals; that is, it takes more energy per gram to power a mouse tha
timama [110]

Answer:

10,200 Cal. per day

Explanation:

The mouse consumes 3.0 Cal each day, and has a mass of 20 grams. We can use this data to obtain a ratio of energy consumption per mass

\frac{3.0 \ Cal}{20 g} = 0.15 \frac{Cal}{g}.

For the human, we need to convert the 68 kilograms to grams. We can do this with a conversion factor. We know that:

1 \ kg = 1000 \ g,

Now, we can divide by 1 kg on each side

\frac{1 \ kg}{1 \ kg} = \frac{1000 \ g}{1 \ kg},

1 = \frac{1000 \ g}{1 \ kg}.

Using this conversion factor, we can obtain the mass of the human in grams, instead of kilograms. First, lets take:

mass_{human} = 68 \ kg

We can multiply this mass for the conversion factor, we are allowed to do this, cause the conversion factor equals 1, and its adimensional

mass_{human} = 68 \ kg * \frac{1000 \ g}{1 \ kg}

mass_{human} = 68,000 g

Now that we know the mass of the human on grams, we can multiply for our ratio of energy consumption

68,000 \ g * 0.15 \frac{Cal}{g} = 10,200 \ Cal

So, we would need 10,200  Cal per day.

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